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7(x-2) - 3x + 5 = -2 (5x-4) + 4 Please help asap! - xxx

Oxana [17]

Answer:

x=

2

3

=1.500

Step-by-step explanation:

(((7•(x-2))-3x)+5)-((0-2•(5x-4))+4) = 0

STEP

2

:

Equation at the end of step 2

((7 • (x - 2) - 3x) + 5) - (12 - 10x) = 0

STEP

3

:

STEP

4

:

Pulling out like terms

4.1 Pull out like factors :

14x - 21 = 7 • (2x - 3)

Equation at the end of step

4

:

7 • (2x - 3) = 0

STEP

5

:

Equations which are never true

5.1 Solve : 7 = 0

This equation has no solution.

A non-zero constant never equals zero.

Solving a Single Variable Equation:

5.2 Solve : 2x-3 = 0

Add 3 to both sides of the equation :

2x = 3

Divide both sides of the equation by 2:

x = 3/2 = 1.500

One solution was found :

x = 3/2 = 1.500

5 0

3 years ago

Read 2 more answers

Need done asap

Stells [14]

Answer:

transitive property

Step-by-step explanation:

According to transitive property, if there is some relation between a and b by some rule , and then there same relation between b and c by some rule, then

A and C are related to each other by some rule.

Example:

A = B

B=C

then by transitive property

A=C

As value of A and C are same that is B we can say that A is equal to C whose value is B.

_______________________________________________

Given

a =2z and 2z=b

here both c and b has value equal to Z , Thus, they follow transitive property.

8 0

3 years ago

1.4x + 1.2x - 3.8 = -9

sashaice [31]

First, to make the equation easier to read, you want to add the x’s together. you should then get 2.6x-3.8=-9. then, you want to add the 3.8 to both sides, to make the x stand alone. you should end up with 2.6x=-5.2. to find x, you then want to divide both sides by 2.6. your final answer after dividing should be x=-2

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=9x-3%20%5Cleqslant%2011x%20-%203" id="TexFormula1" title="9x-3 \leqslant 11x - 3" alt="9x-3 \l

AURORKA [14]

Answer:

0 ≤x

Step-by-step explanation:

9x-3 ≤11x-3

Subtract 9x from each side

9x-9x-3 ≤11x-9x-3

-3 ≤2x-3

Add 3 to each side

-3+3 ≤2x

0 ≤2x

Divide by 2

0/2 ≤2x/2

0 ≤x

6 0

3 years ago

Help evaluating the indefinite integral

Dafna11 [192]

Answer:

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

General Formulas and Concepts:
Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]:
$\displaystyle (cu)' = cu'$

Derivative Property [Addition/Subtraction]:
$\displaystyle (u + v)' = u' + v'$
Derivative Rule [Basic Power Rule]:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Integration

Integrals

Integration Rule [Reverse Power Rule]:
$\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]:
$\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

Step 1: Define

Identify given.

$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx$

Step 2: Integrate Pt. 1

Identify variables for u-substitution/u-solve.

Set u:
$\displaystyle u = 4 - x^2$
[u] Differentiate [Derivative Rules and Properties]:
$\displaystyle du = -2x \ dx$
[du] Rewrite [U-Solve]:
$\displaystyle dx = \frac{-1}{2x} \ du$

Step 3: Integrate Pt. 2

[Integral] Apply U-Solve:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du$
[Integrand] Simplify:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du$
[Integral] Rewrite [Integration Property - Multiplied Constant]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du$
[Integral] Apply Integration Rule [Reverse Power Rule]:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C$
[u] Back-substitute:
$\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }$

∴ we have used u-solve (u-substitution) to find the indefinite integral.

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Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

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Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0

2 years ago