Question

Factor the greatest common factor: −5k2 20k − 30. −1(5k2 − 20k 30) −5(k2 − 4k 6) −5k(k2 − 4k 6) −5(k2 4k − 6)

Answer 1

The greatest common factor−5k2 20k − 30 is  $-5(k^{2} -4k-6).$

What is meant by the greatest common factor?

• The most common factor in mathematics is the highest number that may divide evenly into two other numbers.
• The largest factor that splits both numbers is the greatest common factor. List the prime factors of each integer before calculating the greatest common factor. One 2 and one 3 are shared by those aged 18 and 24. We multiply them to obtain the GCF. Therefore the GCF for 18 and 24 is 2 * 3 = 6.
• The biggest positive integer that divides evenly into all the numbers with no remainder is the greatest common factor (GCF, GCD, or HCF) of a collection of whole numbers.

To find the greatest common factor:

−5k2 20k − 30.

Factor the expression:   $5(-k^{2} +4k-6)$

Factor the expression:   $5(-k^{2} -4k+6)$

Multiply the monomials: $5(k^{2} +4k+6)$

The greatest common factor: $-5(k^{2} -4k-6).$

The greatest common factor−5k2 20k − 30 is $-5(k^{2} -4k-6).$

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Answer 2

The complete question is:

Factor the greatest common factor: $-5k^2+ 20k - 30.$

a) $-1(5k^2- 20k+ 30)$

b) $-5(k^2 -4k+ 6)$

c)$-5k(k^2 - 4k +6)$

d) $-5(k^2 +4k - 6)$

The greatest common factor of −5k² + 20k − 30 exists -5( k² - 4k + 6 ).

Therefore, the correct answer is option a) -5 ( k² - 4k + 6 ).

What is greatest common factor (GCF)?

The greatest common factor (GCF) of a set of numbers exists the biggest factor that all the numbers share.

Given :  −5k² + 20k − 30.

Taking common -5 from each term, we get

−5k² + 20k − 30  = -5 ( k² - 4k + 6 ).

The greatest common factor of −5k² + 20k − 30 exists -5( k² - 4k + 6 ).

Therefore, the correct answer is option a) -5 ( k² - 4k + 6 ).

To learn more about greatest common factor refer to:

brainly.com/question/219464

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