Need help with Trigonometry will mark brainest!!
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<u><em>Answer:</em></u>
Mrs. Hong originally had 900 ml of milk
<u><em>Explanation:</em></u>
The complete question is in the attached image
Assume that the amount of milk Mrs. Hong originally had was x ml
<u>We are given that:</u>
1- She used of it to bake the waffles, <u>therefore</u>:
Amount used in baking waffles = ml
2- She used 300 ml to bake a pie
3- Amount left is half the original amount, <u>therefore</u>:
Amount left = ml
<u>We know that:</u>
Total amount = amount used in waffles + amount used in pie + amount left
<u>Substitute with the givens and solve for x:</u>
Total amount = amount used in waffles + amount used in pie + amount left
<u>This means that:</u>
She originally had 900 ml of milk
Hope this helps :)
Answer: .
Step-by-step explanation:
We know that compresses f(x) vertically such that
- if 0 < a < 1 (a fraction), the graph is compressed vertically by a factor of a units.
- if a > 1, the graph is stretched vertically by a factor of a units.
If we vertically compress the linear parent function, F(x) = x, by multiplying by .
Then, the equation of the new function is .
i.e. .
Answer:
Linear Model: y(x)=35,000+750x
Step-by-step explanation:
In principle <em>Linear Models </em>are employed when we want to define a relationship between an independent and a dependent variable. <em>Linear Models</em> are also known as<em> Functions </em>, where one variable is expressed as a function of <em>at least one</em> other variable. The most common example would be a dependent variable that is directly linked as a response to any changes of an independent variable
. The most common expression of such relationship would be
where
is the relationship factor between
and
and is also known as the <em>slope </em>of the function (representing a rate of change of that function).
In this question we are told that the population of Bay Village today is 35,000. So we know this is our constant variable, lets call it .
Next we know that every year the population is increased by 750 people. So we know that our variable and thus our independent variable is every year which we shall call and our fixed factor is the 750 increment which we will call
.
From that we can conclude that:
<em>Year 1 Population: 35,000</em>
<em>Year 2 Population: 35,000 + 750 = 35,750</em>
<em>Year 3 Population: 35,750 + 750 = 36,500 </em>
And so on and so forth.<em> </em>
So we want to express the above as a Linear Model of the form:
<em> </em>Eqn(1).
Thus from Eqn (1) and all information given (i.e. pluging in values) we finally obtain:
Which for every different value of (i.e. every year) we can obtain the new and increased population
.