System of Equations
For the problem to solve we'll use the following variables:
x = number of the early bird tickets sold
y = number of the regular tickets sold
Haley sold a total of 20 tickets, thus:
x + y = 20 [1]
Early bird tickets cost $10 and regular tickets cost $15, thus the total money collected is:
10x + 15y = 225
Dividing by 5:
2x + 3y = 45 [2]
We have to solve the system of equations [1] and [2].
Multiply [1] by -2:
-2x - 2y = -40 [3]
Add [3] to [2]:
-2x - 2y +2x + 3y = -40 + 45
Simplifying:
y = 5
Substituting in [1]:
x + 5 = 20
Subtracting 5:
x = 20 - 5
x = 15
Solution: Hayley sold 15 early bird tickets and 5 regular-priced tickets
The order pair solution is (15,5)
Answer:
492.84
Step-by-step explanation:
333 x 148÷100
= 492.84
Answer:
$705.79.
Step-by-step explanation:
The formula is
Amount = P(1 + r/100) ^ t so
Amount = 500 (1 + 9/100)^4
= $705.79.
Answer:
20
Step-by-step explanation:
To solve this you have to make a system of equations.
Since the father and son's age sum up to 60, the first equation will be:
f + s = 60
Secondly, since the father's age is 5 times the age of the son 6 years ago the equation will be:
6 - (5s) = f
Now, you have to solve the first equation to let it equal to s
f + s = 60
f = 60 - s
Plug in
6 - 5s = 60 - s
+s +s
6 - 4s = 60
-6 -6
---------------------
-4s = 54
----- -----
-4 -4
s ≅ 14
14 + 6 = 20
