<h3>
Answer:</h3>
- sticker: $35,832
- dealer cost: $26,295.20
<h3>
Step-by-step explanation:</h3>
<em>Sticker Price</em>
The total cost of options is ...
$536 +872 +984 = $2392
The sticker price is ...
sticker price = base price + total options + destination charge
= $32,080 +2,392 +1,360
sticker price = $35,832
<em>Dealer Cost</em>
The dealer gets a discount on the base price and options, but must pay the destination charge.
dealer cost = 0.74×base price + 0.50×total options + destination charge
= 0.74×$32,080 + 0.50×2392 + 1360
dealer cost = $26,295.20
<h3>
Answer: 4(x - 1)(x^2 + x + 1)</h3>
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Work Shown:
4x^3 - 4
4(x^3 - 1)
4(x - 1)(x^2 + x + 1)
In the last step, I used the difference of cubes factoring formula which is
a^3 - b^3 = (a - b)(a^2 + ab + b^2)
Answer: B. Sameer did not use the correct equation
<u>Step-by-step explanation:</u>
12 IS three-fourths OF x
IS: equals
OF: multiplication
48 = 3x
16 = x
The safest way to invest money is to invest in more than one type of investment.
The reason you diversify your investments, is to spread the risk of loss among many different choices. In other words, there is safety in numbers.
Answer:
In 1979 the amount of transistors in a chip was approximately 27865.
Step-by-step explanation:
Since the number of transistors in 1974 was 5000 per chip and it increases at a rate of 41% per year, the number of transistors in a chip per year can be modelled by the following expression:
chips(t) = 5000*(1.41)^(t - 1974)
Therefore in 1979, we have:
chips(1979) = 5000*(1.41)^(1979 - 1974)
chips(1979) = 5000*(1.41)^5
chips(1979) = 27865.4183
In 1979 the amount of transistors in a chip was approximately 27865.
