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Verizon [17]
2 years ago
5

Which type of statistical test is appropriate to analyze the primary efficacy endpoint in this study?

Mathematics
1 answer:
Hitman42 [59]2 years ago
4 0

The chi-square test is appropriate to analyze the primary efficacy endpoint in this study

The chi-square test is a valid statistical hypothesis test when the test statistic is chi-square distributed under the null hypothesis. Specifically, Pearson's chi-square test and its variants. Used to compare observed and expected results. The purpose of this test is to determine whether differences between observed and expected data are due to chance or to relationships between the variables being examined.

A chi-square formula is a statistical formula for comparing two or more sets of statistical data. It is used for data consisting of variables that span different categories and is denoted by χ2. The chi-square formula is χ2 = ∑(Oi – Ei)2/Ei, where Oi = observed (actual) and Ei = expected.

Learn more about the chi-square test here: brainly.com/question/4543358

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Which expression is the exponential form of square root of 9 y
zvonat [6]
Answer: 3 * y^(1/2)

Work:
Since the exponential form of any number is simply the number shown as broken down into its smallest pieces, you need to make each term exponential. Its helpful to break the 9 and the y apart when solving this and bring them back at the end. The expression then becomes (square root of 9) * (square root of y).

The square root of 9 can be simplified to 3. 

The square root of y cannot be simplified but can be written in a form such that it becomes y^(1/2). The square root of any number is equal to that same number to the 1/2 power. 

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The graph shows the height of a staircase in inches based on a certain number of stairs.According to the function in the graph,
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Read 2 more answers
Convert the given exponential function to the form indicated. Round all coefficients to four significant digits. HINT [See Examp
shtirl [24]
1) Take natural logarithms (Ln) on both sides of the first equation:

f(t) = 18 [0.887]^t => Ln [f(t) ] = Ln (18) + t Ln(0.887)

2) Take natural lograrithms (Ln) on both sides of the second equation:

f(t) = Qo [e] ^ (-kt) => Ln [f(t) ] = Ln(Qo) - kt

3) Make the coefficients equal=>

Ln (Qo) = Ln(18) => Qo = 18

Ln (0.887) = - k => -k = -0.1199

4) Substitute the terms in f(t) = Qo [e]^ (-kt) =>

f(t) = 18 [e]^ (  -0.1199 t)

Answer: 18 [e]^(- 0.1199t)


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