SOMEONE PLEASE HELP ME

Write a rule for the linear function in the graph.

Nata [24]

Y=4x-13

that is the line

4 0

4 years ago

There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In

Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the sampling distribution of the sampling proportions.

The mean and standard deviation of this sampling distribution is:

$\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}$

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

$P(0.45$

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

$z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)$

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

$P(p>0.8)=P(z>z^*)$

The z value is calculated as before:

$z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0$

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0

3 years ago

Please help me asap! Thank you!

blsea [12.9K]

......bruh okay......

3 0

3 years ago

PLZZZZZZZZZZZZZZZZ HELP

Slav-nsk [51]

Answer:

The first box in the girl row is 18, the second one in the boy row is 8, and the bottom one is also 18.

Step-by-step explanation:

To get 81 to 9, you have to divide by 9, which means you have to do the same to 72. You get the ration 9 to 8, 9 being girls and 8 being guys. Then to get from 8 guys to 16, you have to multiply by 2, which means you do the same to 9 and get the answer of 18 girls. Hope this helps :)

5 0

3 years ago

Nanna's Italian Restaurant has collected data about customer sauce orders. It calculated that P(marinara) = 0.64, P(alfredo) = 0

abruzzese [7]

To answer this question, apply this formula P(m and a) = P(m) + P(a) - P(m or a). Where m stands for marinara and a stands for alfredo.

P(m and a) = P(m) + P(a) - P(m or a)
P(m and a) = 0.64 + 0.56 - 0.89
P(m and a) = 0.31

5 0

3 years ago