3 years ago

WILL GIVE BRAINLIEST

Mathematics

2 answers:

Alekssandra [29.7K]3 years ago

5 0

I think 2 mistakes I think

Valentin [98]3 years ago

5 0

If the lines intersect at one point, there is ONE solution.

If the lines were parallel, they would never intersect so there would be no solutions.

If the lines were the same line, they would intersect at every point so there would be infinite solutions.

Answer: ONE solution

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2 years ago

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deff fn [24]

Step-by-step explanation:

Given equation of circle is,

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${x}^{2} + {(y - k)}^{2} = 21 \\ or \: {x}^{2} + {y}^{2} - 2ky + {k}^{2} - 21 = 0 \\ by \: compairing \:it \: with \: \\ {x}^{2} + {y}^{2} + 2gx + 2fy = 0 \: we \: get \\ g = 0 \\f = - k \\ c = {k}^{2} - 21$

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3 years ago