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mr Goodwill [35]
2 years ago
10

LAB: Parsing dates Complete main() to read dates from input, one date per line. Each date's format must be as follows: March 1,

1990. Any date not following that format is incorrect and should be ignored. Use the substr() function to parse the string and extract the date. The input ends with -1 on a line alone. Output each correct date as: 3/1/1990 Ex: If the input is March 1, 1990 April 2 1995 7/15/20 December 13, 2003 -1 then the output is: 3/1/1990 12/13/2003 LAB ACTIVITY 9.10.1: LAB: Parsing dates 0/10 main.cpp Load default template - COLE > 5 6 int DateParser(string month) 7 int monthInt = 0; if (month January) 10 monthint - 11 11 else if (month -- "February") 12 monthint - 21 13 else if (month - "March) montrent - 3; 15 else if (month -- "April") 16 monthInt - 4 else if (month "ay") monthint - 5 19 else if (month June") antin 6 21 else if (monthuly) 22 monthint - 7 else if (monthst") monthiet 8 LAB ACTIVITY 9.10.1: LAB: Parsing dates main.cpp 22 monthint - 1 23 else if (month == "August") 24 monthInt = 8; 25 else if (month - "September") 26 monthInt = 9; 27 else if (month -- "October") 28 monthInt - 10; 29 else if (month - "November") 30 monthInt - 11; 31 else if (month - "December") 32 monthInt = 12; 33 return monthint; 34 ) I 35 36 int main() { 37 38 // TODO: Read dates from input, parse the dates to find the one 39 1 in the correct format, and output in m/d/yyyy format 40 41) 42
Computers and Technology
1 answer:
Vladimir [108]2 years ago
6 0

The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:

<h3>Python code</h3>

import datetime

inputs = []

result = []

#read the inputs

date = input()

inputs.append(date)

while not date == "-1":

 date = input()

 inputs.append(date)

#check if the input is in the correct format and convert it.

for date_text in inputs:

 try:

   date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")

   result.append(date_text.strftime("%d/%m/%Y"))

 except ValueError:

   pass

   

print(*result, sep = "\n")

The above code would parse the string and extract the date. The split() method was used to break the input into tokens.

Read more about python programming here:

brainly.com/question/27666303

#SPJ1

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Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

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{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

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this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

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this->a = a;//assigning value in a variable

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void setB(double b)//defining a set method to hold value in parameter  

{

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{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

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{

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if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

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cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

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}

}

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{

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int main()//defining main method  

{

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q.print();//calling print method

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q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

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Answer:

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Explanation:

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