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mr Goodwill [35]
2 years ago
10

LAB: Parsing dates Complete main() to read dates from input, one date per line. Each date's format must be as follows: March 1,

1990. Any date not following that format is incorrect and should be ignored. Use the substr() function to parse the string and extract the date. The input ends with -1 on a line alone. Output each correct date as: 3/1/1990 Ex: If the input is March 1, 1990 April 2 1995 7/15/20 December 13, 2003 -1 then the output is: 3/1/1990 12/13/2003 LAB ACTIVITY 9.10.1: LAB: Parsing dates 0/10 main.cpp Load default template - COLE > 5 6 int DateParser(string month) 7 int monthInt = 0; if (month January) 10 monthint - 11 11 else if (month -- "February") 12 monthint - 21 13 else if (month - "March) montrent - 3; 15 else if (month -- "April") 16 monthInt - 4 else if (month "ay") monthint - 5 19 else if (month June") antin 6 21 else if (monthuly) 22 monthint - 7 else if (monthst") monthiet 8 LAB ACTIVITY 9.10.1: LAB: Parsing dates main.cpp 22 monthint - 1 23 else if (month == "August") 24 monthInt = 8; 25 else if (month - "September") 26 monthInt = 9; 27 else if (month -- "October") 28 monthInt - 10; 29 else if (month - "November") 30 monthInt - 11; 31 else if (month - "December") 32 monthInt = 12; 33 return monthint; 34 ) I 35 36 int main() { 37 38 // TODO: Read dates from input, parse the dates to find the one 39 1 in the correct format, and output in m/d/yyyy format 40 41) 42
Computers and Technology
1 answer:
Vladimir [108]2 years ago
6 0

The python code which can be used to read dates from input, one date per line and each date's format must be as follows: March 1, 1990, is:

<h3>Python code</h3>

import datetime

inputs = []

result = []

#read the inputs

date = input()

inputs.append(date)

while not date == "-1":

 date = input()

 inputs.append(date)

#check if the input is in the correct format and convert it.

for date_text in inputs:

 try:

   date_text = datetime.datetime.strptime(date_text,"%d %B, %Y")

   result.append(date_text.strftime("%d/%m/%Y"))

 except ValueError:

   pass

   

print(*result, sep = "\n")

The above code would parse the string and extract the date. The split() method was used to break the input into tokens.

Read more about python programming here:

brainly.com/question/27666303

#SPJ1

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Answer:

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def split(X):

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X = []

n = int(input("Length of X: "))

for i in range(n):

   inp = int(input(": "))

   X.append(inp)

   

if len(X) == 0 or len(X) == 1:

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The following represents the split function in the previous problem

def split(X):

This initializes L and G to empty lists

   L = []; G = []

This iterates through X

   for i in range(len(X)):

All elements of X greater than 0 equal to the first element are appended to G

      <em> if X[i]>=X[0]:</em>

<em>            G.append(X[i])</em>

Others are appended to L

<em>        else:</em>

<em>            L.append(X[i])</em>

This sorts L and G

   L.sort(); G.sort()

This returns sorted lists L and G

   return L,G

The main function begins here

This initializes X

X = []

This gets the length of list X

n = int(input("Length of X: "))

This gets input for list X

<em>for i in range(n):</em>

<em>    inp = int(input(": "))</em>

<em>    X.append(inp)</em>

This prints X is X is empty of has 1 element

<em>if len(X) == 0 or len(X) == 1:</em>

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If otherwise

else:

This calls the split function to split X into 2

   X1,X2=split(X)

This merges the two lists returned (sorted)

   newList = sorted(X1 + X2)

This prints the new list

   print(newList)

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