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guajiro [1.7K]
3 years ago
13

In country​ A, the number of highway bridges for the years 2000 to 2005 can be modeled by the equation y=149(x+1.5)^2+489,505, w

here x=0 represents the year 2000. Assume that this trend continued and find the year in which there were 505,000 highway bridges in country A.
Mathematics
1 answer:
EleoNora [17]3 years ago
4 0
Given that the number of bridges has been modeled by the function:
<span>y=149(x+1.5)^2+489,505
To find the year in which, y=505000 we shall proceed as follows:
From:
</span>y=149(x+1.5)^2+489,505
substituting y=505000 we shall have:
505000=149(x+1.5)^2+489,505
simplifying the above we get:
0=149(x+1.5)^2-15495
expanding the above we get:
0=149x^2+447x+335.25-15495
simplifying
0=149x^2+447x-15159.8
solving the quadratic equation by quadratic formula we get:
x~8.69771 or x~-11.6977
hence we take positve number:
x~8.69771~8.7 years~9 years
thus the year in which the number will be 505000 will be:
2000+9=2009
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Read 2 more answers
If 3 * 9 + 2y = 47 what is the value of y
docker41 [41]
Answer: 10

Why?
3*9+2y=47
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