What is 196 classified as

Mathematics

1 answer:

pashok25 [27]3 years ago

5 0

Answer:

it is so unclear to say . If any more information is given, then only it can be answered. I don't think 196 is so special to be classified.

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Alice and Becky live on Parkway East, at the intersections of Owens Bridge and Bay Bridge, respectively. Carl and

guajiro [1.7K]

I think the answer is C

6 0

2 years ago

How does the order of the numbers affect the product in multiplication problems

GalinKa [24]

Answer:

Uneffected.

Step-by-step explanation:

The order of the numbers doesn't affect the product in multiplication problems.

For example, we need to multiply 2 × 10.

We can write it as : 2×5×2

2×(5×2) = 2×10 = 20

Also,

(2×5)×2 = 10×2 = 20

Hence, it will remain unaffected when we multiply numbers.

7 0

3 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :