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Marat540 [252]
2 years ago
14

Evaluate the given integral by using substitution method:

5sin%28%5Cfrac%7B2%5Cpi%20%7D%7Bx%7D%20%29%7D%7Bx%5E%7B2%7D%20%7D%20%7D%20%5C%2C%20dx" id="TexFormula1" title="\int\limits^a_b {\frac{5sin(\frac{2\pi }{x} )}{x^{2} } } \, dx" alt="\int\limits^a_b {\frac{5sin(\frac{2\pi }{x} )}{x^{2} } } \, dx" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Veronika [31]2 years ago
5 0

Step-by-step explanation:

substitute the angle of sine with a variable and differentiate

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When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is a
Lyrx [107]

Answer:

A) 0

Step-by-step explanation:

When x is divided by 11, we have a quotient of y and a remainder of 3

x/11 = y + 3

x = 11y + 3 ........(1)

When x is divided by 19, we have a remainder of 3 also

x/19 = p + 3 (p = quotient)

x = 19p + 3 ..........(2)

Equate (1) and (2)

x = 11y + 3 = 19p + 3

11y + 3 = 19p + 3

11y = 19p + 3 -3

11y = 19p

Divide both sides by 11

11y/11 = 19p/11

y = 19p/11

y and p are integers. 19 is a prime number. P/11 is also an integer

y = 19(integer)

This implies that y is a multiple of 19. When divided by 19, there is no remainder. The remainder is 0

8 0
3 years ago
Calculus piecewise function. ​
Kipish [7]

Part A

The notation \lim_{x \to 2^{+}}f(x) means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows \lim_{x \to 2^{+}}f(x) = 2

Then for the left hand limit \lim_{x \to 2^{-}}f(x), we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, \lim_{x \to 2^{-}}f(x) = 1

===============================================================

Part B

Because \lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x) this means that the limit \lim_{x \to 2}f(x) does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since \lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3, this means the limit \lim_{x \to 4}f(x) does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0
2 years ago
X=7 what is 3x pleasee help i need this by tomorrow ​
Romashka [77]

Answer:

x = 7 \\ 3x = 3(7) = 21

hope helpful <3

4 0
2 years ago
Order the following integers from least to greatest. Then plot them on the number line.
Semenov [28]

Answer:

-7,-5,-4,-2,1,3,4,6,8,9

Step-by-step explanation:

6 0
3 years ago
(5) Math problem with picture
lesantik [10]
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5 0
4 years ago
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