Answer:
v=9i+3j
Step-by-step explanation:
The given vector, v has initial point at P1 = (−5, −2) and terminal point at P2 = (4, 1).
The vector v is found by subtraction the initial point from the terminal point.
v=<4,1>-<-5,-2>
v=<4--5,1--2>
v=<9,3>
We write v as multiples of the basis vectors to obtain:
v=9i+3j
Answer: 16/81 (x-10)^2 -4
Step-by-step explanation:
To write a vertex equation with just a point and the vertex, you have to figure out the variables.
In vertex form, the equation is y = a (x-h)^2 + k
Your y is 12, x = 1, h = 10, and k = -4
Plug everything into equation
12 = a (1 - 10)^2 -4
12 = a (-9)^2 - 4
12 = 81a - 4
16 = 81a
16/81 = a
Now you know what the 'a' value is.
If you graph 16/81 (x-10)^2 -4 , you will get a point at (1,12) and a vertex of (10,-4)!
I hope this helps!
3.14 * 3 * 6 = 56.52 cubic inches. Hope this helps. :)
Answer:
the side lengths
Step-by-step explanation:
