Determine o vértice da função quadrática y=16x²-6x-10
1 answer:
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Answer:
dy/dx =
Step-by-step explanation:
-y + 2x²- x = -5y³
2x² - x = y - 5y³
4x - 1 = dy/dx - 15y².dy/dx
dy/dx(1 - 15y²) = 4x - 1
dy/dx =
Answer:
dy/dx =
Step-by-step explanation:
-y + 2x²- x = -5y³
2x² - x = y - 5y³
4x - 1 = dy/dx - 15y².dy/dx
dy/dx(1 - 15y²) = 4x - 1
dy/dx =