3 years ago

I need y’all helpppp

Mathematics

1 answer:

docker41 [41]3 years ago

6 0

Answer:

the answer is A

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The graph of the parent function f(x) = x3 is transformed such that g(x) = f(–2x). How does the graph of g(x) compare to the gra

Anni [7]

Answer:

b) g(x) is stretched horizontally and reflected over the x-axis.

Step-by-step explanation:

The given parent function is

$f(x) = {x}^{3}$

The transformed function is

$g(x) = f (- 2x)$

We want to see how the transformed graph compares with the parent graph.

The negation inside means all x-coordinates we're negated.

This means, there is a reflection in the y-axis.

The factor of 2 within the function means a horizontal stretch by a factor of 1/2.

The correct answer is B.

8 0

3 years ago

Read 2 more answers

assume that women's heights are normally distributed with a mean of 63.6 inches and a standard deviation of 2.5 inches. find the

drek231 [11]

Answer:

65.3658 inches

Step-by-step explanation:

Let X be the height of a woman randomly choosen. We know tha X have a mean of 63.6 inches and a standard deviation of 2.5 inches. For an x value, the related z-score is given by z = (x-63.6)/2.5. We are looking for a value $x_{0}$ such that $P(X < x_{0}) = 0.76$ , but, $0.76 = P(X < x_{0}) = P((X-63.6)/2.5 < (x_{0}-63.6)/2.5) = P(Z < (x_{0}-63.6)/2.5)$ , i.e., $(x_{0}-63.6)/2.5$ is the 76th percentile of the standard normal distribution. So, $(x_{0}-63.6)/2.5 = 0.7063$ , $x_{0} =63.6+(2.5)(0.7063) = 65.3658$ . Therefore, the height of a woman who is at the 76th percentile is 65.3658 inches.