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kozerog [31]
1 year ago
12

Find the x- and y-intercept of the parabola y = x² + 4x + 2

Mathematics
1 answer:
Veronika [31]1 year ago
4 0

Answer:

x-intercept = (- 2 + √2, 0) (- 2 - √2, 0)

y-intercept = (2, 0)

Step-by-step explanation:

<u>Given expression</u>

y = x² + 4x + 2

<u>Find the x-intercept</u>

<em>Definition of x-intercept is the point that intersects with the x-axis, which means the y value is 0</em>

(0) = x² + 4x + 2

(x + 2 - √2) (x + 2 + √2) = 0

x = -2 ± √2

Therefore, the x-intercepts are \Large\boxed{(-2+\sqrt{2},~0) } \Large\boxed{(-2-\sqrt{2},~0) }

<u>Find the y-intercept</u>

<em>Definition of x-intercept is the point that intersects with the y-axis, which means the x value is 0</em>

y = (0)² + 4(0) + 2

y = 0 + 0 + 2

y = 2

Therefore, the y-intercept is \Large\boxed{(0,~2)}

Hope this helps!! :)

Please let me know if you have any questions

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