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3 years ago

Solve the system of linear equations.

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

1. No solution

2. Infinite solutions

Step-by-step explanation:

1. To solve the system, set the equations equal to each other and solve for x.

2x - 5 = 2x + 7

-5 = 7

This is a false statement. This means there is no solution.

2. To solve the system, graph each equation.

y = -3/4 x - 5/2 has a y-intercept -5/2 and slope -3/4.

3x + 4y = -10 converts to y = -3/4x -5/2.

This graphs as the exact same line. This system has infinite solutions.

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A rotating lawn sprinkler sprays water in a circular area of grass as shown in the picture. The diameter of the circular area of

Georgia [21]

Answer:

$9\pi \: \mathrm{ft^2\:or}\: 28.27 \mathrm{\: ft^2}$

Step-by-step explanation:

The area of a circle is given by $r^2\pi$ where $r$ is the radius of the circle. The diameter is given as $6$ feet, so the radius of this circle is $\frac{6}{2}=3$ feet.

Plugging in our values, we get:

$3^2\pi=9\pi\approx28.27$ .

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2 years ago

Michelle's class is handing out balloon arrangement consisting of 4 balloons each each balloon has and equally likely chance of

lara [203]

Answer:

The answer is 1/30 or 0.0333333...

Step-by-step explanation:

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3 years ago

thomas has 6.35 in dimes and quarters the number of dimes is three more than three times the number of quarters how many quarts

Feliz [49]

Answer:

11 quarters

Step-by-step explanation:

If Thomas ignores the extra 3 dimes, he can arrange his coins in groups of 3 dimes and 1 quarter, each group valued at 55¢. It takes

... 6.05/0.55 = 11

groups to bring the total value to the $6.05 remaining after ignoring the extra dimes.

Thomas has 11 quarters and 36 dimes.

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4 years ago

Cos 4θ − cos 2θ = sin θ

hichkok12 [17]

$cos(4\theta) - cos(2\theta) = sin(\theta)$
$-2sin(\frac{4\theta + 2\theta}{2})sin(\frac{4\theta - 2\theta}{2}) = sin(\theta)$
$-2sin(\frac{6\theta}{2}sin\frac{2\theta}{2}) = sin(\theta)$
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$\frac{-2sin(3\theta)sin(\theta)}{-2sin(\theta)} = \frac{sin(\theta)}{-2sin(\theta)}$
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$sin^{-1}[sin(3\theta)] = sin^{-1}(-\frac{1}{2})$
$3\theta = -30$
$\frac{3\theta}{3} = \frac{-30}{3}$
$\theta = -10$

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