All categories

3 years ago

Solve the system of linear equations.

Mathematics

1 answer:

RoseWind [281]3 years ago

4 0

Answer:

1. No solution

2. Infinite solutions

Step-by-step explanation:

1. To solve the system, set the equations equal to each other and solve for x.

2x - 5 = 2x + 7

-5 = 7

This is a false statement. This means there is no solution.

2. To solve the system, graph each equation.

y = -3/4 x - 5/2 has a y-intercept -5/2 and slope -3/4.

3x + 4y = -10 converts to y = -3/4x -5/2.

This graphs as the exact same line. This system has infinite solutions.

You might be interested in

A cab company charges $10.00 per ride plus an additional .75 per mile write the problem in slope intercept form

Natalija [7]

Well the dependent variable is .75, and the independent variable is 10.

So,
.75x + 10 would be the equation, the number of miles representing x.

8 0

3 years ago

Yesterday's afternoon temperature was 21*F. It plunged overnight to 3*F. How many degrees did the temperature drop? I think the

Igoryamba

Answer: its D) 24

Step-by-step explanation:

For your answer i have checked and it is correct it is D) 24

7 0

3 years ago

1. A translation of function f is f1(x) = b(x – h). It is equivalent to

svetoff [14.1K]

4 will be the correct answer to your question

7 0

3 years ago

In if GS ⊥ XJ and XJ⊥EA what is true about GS and EA

svlad2 [7]

Answer:

( $GS$ ) || ( $EA$ )

Step-by-step explanation:

When two lines are parallel, all four angles formed by the intersection of the two lines are right angles, meaning their angle measures are (90°). This means that alternate interior angles are congruent because all alternate interior angles measures equal (90°). Therefore, by the alternate interior angles converse theorem, lines ( $GS$ ) and ( $EA$ ) are parallel.

The alternate interior angles converse theorem states if two angles are congruent and they have the relation of being a part of two lines intersected by a third line, then the two non-intersecting lines are parallel.

6 0

3 years ago

Read 2 more answers

A fourth degree polynomial with real coefficients can have -4, 8i,+4i, and as its zeros. True or false? Justify your answer.

liraira [26]

You didn't give the fourth zero, but the answer is still false. If you have a root or an imaginary number as a zero, then its conjugate is also a zero. So if 8i is a zero, then -8i must also be a zero, and if 4i is a zero, then -4i must be a zero, with those zeros and -4, the number of zeroes exceeds the number of zeroes that a fourth degree polynomial can have.

4 0

3 years ago