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Len [333]
3 years ago
9

Solve for x. x/8+x/10=9/8 Simplify your answer as much as possible.

Mathematics
1 answer:
BabaBlast [244]3 years ago
6 0

Answer:

<em>I</em><em> hope</em><em> it's</em><em> helps</em><em> you</em>

<em>have</em><em> a</em><em> nice</em><em> day</em>

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one x-intercept for a parabola is at the point (2, 0). use the quadratic formula to find the other x-intercept for the parabola
omeli [17]

Answer:

Step-by-step explanation:

There are 3 ways to find the other x intercept.

1) Polynomial Long Division.

Divide x^2 - 3x + 2 by the binomial x - 2, because by the Factor Theorem if a is a root of a polynomial then x - a is a factor of said polynomial.

2) Just solving for x when y = 0, by using the quadratic formula.

x^2 - 3x + 2 = 0\\x_{12} = \frac{3 \pm \sqrt{9 - 4(1)(2)}}{2} = \frac{3 \pm 1}{2} = 2, 1.

So the other x - intercept is at (1, 0)

3) Using Vietta's Theorem regarding the solutions of a quadratic

Namely, the sum of the solutions of a quadratic equation is equal to the quotient between the negative coefficient of the linear term divided by the coefficient of the quadratic term.

x_1 + x_2 = \frac{-b}{a}

And the product between the solutions of a quadratic equation is just the quotient between the constant term and the coefficient of the quadratic term.

x_1 \cdot x_2 = \frac{c}{a}

These relations between the solutions give us a brief idea of what the solutions should be like.

6 0
3 years ago
How is a tangent different from a chord
Akimi4 [234]
In a tangent segment, no part of it is in the interior of the circle. with a secant, there is a part in the interior called the chord. hope it helps
if you need help with anything else just ask me 
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3 years ago
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What is it please hurry im timed<br>​
lorasvet [3.4K]
The answer is -1.5, 3.5
4 0
3 years ago
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PLEASE HELP WILL GIVE BRAINLIEST!!!
Amanda [17]

Answer:

angle U ( the third option down)

Step-by-step explanation:

5 0
3 years ago
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What is the factored form of 16x2 – 16x – 12?
crimeas [40]
Q1. The answer is 4(2x - 3)(2x + 1)

16x² – 16x – 12 = 4 * 4x² - 4 * 4x - 4 * 3 =
                          = 4(4x² - 4x - 3) =
                          = 4(4x² + 2x - 6x - 3) = 
                          = 4(2x * 2x + 2x - (2x * 3 + 3)) =
                          = 4(2x(2x + 1) - (3(2x + 1))) =
                          = 4((2x + 1)(2x - 3)) =
                          = 4(2x - 3)(2x + 1)


Q2. The answer is 3(x + 8)(x - 1)

3x² + 21x – 24 = 3 * x² + 3 * 7x - 3 * 8 =
                         = 3(x² + 7x - 8) =
                         = 3(x *x - x + 8x - 8) =
                         = 3((x(x - 1) + 8(x - 1)) =
                         = 3(x + 8)(x - 1)
8 0
3 years ago
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