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Arlecino [84]
2 years ago
7

Question 1 of 28

Physics
1 answer:
amm18122 years ago
5 0

Answer: D. They are the coldest stars.

Explanation:

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A 100 kg cart goes around the inside of a vertical loop of a roller coaster. The radius of the loop is 3 m and the cart moves at
Leya [2.2K]

The centripetal force acting on the object is 1200N

<u>Explanation:</u>

Given-

mass, m = 100kg

radius, r = 3m

Velocity, v = 6m/s

Force, F = ?

When an object moves in a circular motion, then centripetal force acts on it.

We know,

Centripetal force, Fc = mv²/r

                             Fc = 100 X \frac{6^2}{3} \\\\

                             Fc = 1200N

Therefore, the centripetal force acting on the object is 1200N

7 0
4 years ago
Which major planet has the largest . . .
svlad2 [7]

Answer:

Answered

Explanation:

The largest Semi major axis- Neptune( 30.0611 AU).

Largest avg. Orbital speed around the Sun- 47.9 km/s of mercury.

The Largest orbital period around the Sun- 164.79 years for Neptune by 1 year on Earth.

The largest Eccentricity of orbit- is Of Mercury (0.206)

Note: All data has been taken from the internet, hope it helps

7 0
3 years ago
A railroad car of mass M moving at a speed v1 collides and couples with two coupled railroad cars, each of the same mass M and m
Tatiana [17]

Answer:

Explanation:

Given

mass of each railroad is M

first railroad is moving with velocity v_1 and other two's with v_2

conserving Momentum

Mv_1+2Mv_2=3M v_f

where v_f is the final velocity of combined system

v_f=\frac{v_1+2v_2}{3}

(b)Initial Kinetic Energy

=\frac{1}{2}Mv_1^2+\frac{1}{2}2Mv_2^2

=\frac{1}{2}Mv_1^2+Mv_2^2

Final Kinetic Energy

=\frac{1}{2}3Mv_f^2=\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)

Loss in Kinetic Energy

=\frac{1}{2}Mv_1^2+Mv_2^2-\frac{1}{6}M(v_1^2+4v_2^{2}+4v_{1}v_2)

=M(v_1-v_2^2)^2

7 0
4 years ago
What is the difference between amplitude modulation and frequency modulation​
elena-s [515]

Answer:

Explanation:

Difference Between AM And FM. ... The main difference between both modulations is that in frequency modulation, the frequency of the carrier wave is modified as per the transmit data, while in amplitude modulation, the carrier wave is modified according to the data.

3 0
3 years ago
Read 2 more answers
A 1500-nF capacitor with circular parallel plates 2.0 cm in diameter is accumulating charge at the rate of 40.0 mC/s at some ins
Delvig [45]

Answer:

B= 1.14 X 10^{-7} Tesla

Explanation:

B at point 7.0 cm radially outward is to find out?

Now for field strength in case of parallel plates in given as

        B=\frac{I\mu}{2r\pi}

        B=\frac{4\pi X 10^{-7} \frac{Tm}{A}X40 X10^{-3} \frac{C}{s}}{2X0.07mX\pi}

      B= 1.14 X 10^{-7} Tesla

For the second part as Capacitor is fully charged no more flow of current could take place hence

I= Current =o

so B = 0

6 0
3 years ago
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