a) PE=mgh=0.2*9.8*1.2=2.352 J
b) KE=PE=2.352 J
c)
m/s
Answer:9.34 A/s
Explanation:
Given
radius of solenoid 
Emf induced 
no of turns per meter n=450
we know Induced EMF is given by

Magnetic Field is given by

thus 
Area of cross-section
where
solving integration we get

where r=distance from axis
R=radius of Solenoid



Answer:
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Answer:
17.565 kgm/s
Explanation:
Momentum = mass × velocity
I = mv..................... Equation 1
But we can calculate the value of v using the equation of motion under gravity.
v² = u²+2gs............. Equation 2
Where u = initial velocity, s = maximum heigth, g = acceleration due to gravity.
Given: u = 0 m/s (at the maximum heigth), s = 7.0 m.
Constant: g = 9.8 m/s²
Substitute these values into equation 2
v² = 0²+ 2×7×9.8
v² = 137.2
v = √137.2
v = 11.71 m/s.
Also given: m = 1.50 kg
substitute these values into equation 1
Therefore,
I = 1.5×11.71
I = 17.565 kgm/s