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kotykmax [81]
3 years ago
15

Choose the correct statement concerning electrical circuits. A) The electrons in a circuit move from the positive to the negativ

e battery terminal. B) In a circuit, when the resistance is increased the current increases. C) In a circuit, when the battery voltage is increased the current increases. D) In a circuit, when the battery voltage is increased the current decreases. E) Any standard alkaline battery (AAA, AA, C, D) has a voltage of 5 V.
Physics
1 answer:
zavuch27 [327]3 years ago
7 0

Answer: C

Explanation:

when more volts are in a battery the more current you receive.

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What is the mass of a man who accelerates 4 m/s2 under the action of a 200 N net force?
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Answer:

\huge  \boxed{ \boxed{50 \:   kg }}

Explanation:

The mass of the man can be found by using the formula

m =  \frac{f}{a}  \\

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a is the acceleration

From the question we have

m =  \frac{200}{4}  \\

We have the final answer as

<h3>50 kg</h3>

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An isolated conducting sphere has a 17 cm radius. One wire carries a current of 1.0000020 A into it. Another wire carries a curr
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14 ms is required to reach the potential of 1500 V.

<u>Explanation:</u>

The current is measured as the amount of charge traveling per unit time. So the charge of electrons required for each current is determined as the product of current with time.

       Charge = Current \times Time

As two different current is passing at two different times, the net charge will be the different in current.  So,

        \text { Charge }=(1.0000020-1.0000000) \times t=2 \times 10^{-6} \times t

The electric voltage on the surface of cylinder can be obtained as the ratio of charge to the radius of the cylinder.

        V=\frac{k q}{R}

Here k = 9 * 10^9, q is the charge and R is the radius. As q=2 \times 10^{-6} \times t and R =17 cm = 0.17 m, then the voltage will be

        V=\frac{9 \times 10^{9} \times 2 \times 10^{-6} \times t}{0.17}

The time is required to find to reach the voltage of 1500 V, so

1500 =\frac{9 \times 10^{9} \times 2 \times 10^{-6} \times t}{0.17}

\begin{aligned}&t=\frac{1500 \times 0.17}{\left(9 \times 10^{9} \times 2 \times 10^{-6}\right)}\\&t=14.1666 \times 10^{-3} s=14\ \mathrm{ms}\end{aligned}

So, 14 ms is required to reach the potential of 1500 V.

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