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3 years ago

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Choose the correct statement concerning electrical circuits. A) The electrons in a circuit move from the positive to the negativ

e battery terminal. B) In a circuit, when the resistance is increased the current increases. C) In a circuit, when the battery voltage is increased the current increases. D) In a circuit, when the battery voltage is increased the current decreases. E) Any standard alkaline battery (AAA, AA, C, D) has a voltage of 5 V.

1 answer:

zavuch27 [327]3 years ago

7 0

Answer: C

Explanation:

when more volts are in a battery the more current you receive.

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Suppose Gabor, a scuba diver, is at a depth of 15m. Assume that: The air pressure in his air tract is the same as the net water

s2008m [1.1K]

Complete Question

The complete question is shown on the first and second uploaded image

Answer:

a

Now the ratio of the gases in Gabor's lungs at the depth of 15m to that at

the surface is $\frac{(n/V)_{15\ m}}{(n/V)_{surface}} = 2.5$

b

The number of moles of gas that must be released is $n= 0.3538\ mols$

Explanation:

We are told from the question that the pressure at the surface is 1 atm and for each depth of 10m below the surface the pressure increase by 1 atm

This means that the pressure at the depth of the surface would be

$P_d = [\frac{15m}{10m} ] (1 atm) + 1 atm$

$= 2.5 atm$

The ideal gas equation is mathematically represented as

$PV = nRT$

Where P is pressure at the surface

V is the volume

R is the gas constant = 8.314 J/mol. K

making n the subject we have

$n = \frac{PV}{RT}$

Considering at the surface of the water the number of moles at the surface would be

$n_s = \frac{P_sV}{RT}$

Substituting $1 atm = 101325 N/m^2$ for $P_s$ , $6L = 6*10^{-3}m^3$ for volume , 8.314 J/mol. K for R , (37° +273) K for T into the equation

$n_s = \frac{(1atm)(6*10^{-3} m^3)}{(8.314J/mol \cdot K)(37 +273)K}$

$= 0.2359 mol$

To obtain the number of moles at the depth of the water we use

$n_d = \frac{P_d V}{RT}$

Where $P_d \ and \ n_d \$ are pressure and no of moles at the depth of the water

Substituting values we have

$n_d = \frac{(2.5)(101325 N/m^2)(6*10^{-3}m^3)}{(8.314 J/mol \cdot K)(37 + 273)K}$

$= 0.5897 mol$

Now to obtain the number of moles released we have

$n = n_d - n_s$

$= 0.5897mol - 0.2359mol$

$=0.3538 \ mol$

The molar concentration at the surface of water is

$[\frac{n}{V} ]_{surface} = \frac{0.2359mol}{6*10^-3m^3}$

$=39.31mol/m^3$

The molar concentration at the depth of water is

$[\frac{n}{V} ]_{15m} = \frac{0.5897}{6*10^{-3}}$

$= 98.28 mol/m^3$

Now the ratio of the gases in Gabor's lungs at the depth of 15m to that at the surface is

$\frac{(n/V)_{15\ m}}{(n/V)_{surface}} = \frac{98.28}{39.31} =2.5$

6 0

3 years ago

Which copper wire would have the highest resistance?

Dafna11 [192]

Answer:

Just consider the resistance as water flowing through a pipe. If the pipe is too small in radius (consider thin wire as small pipe) water can’t flow easly. If the pipe is big in radius (consider thick wire as big pipe) water can flow easly. So flowing water through a small pipe for a long distance will inversly affect the normal flow where as flowing water through a big pipe for a small distance will not affect too much the normal flow.

So long & thin wire has high resistance. Short & thick wire has low resistance.

B. A wire that is 2 m long and has a cross-sectional area of 0.066

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3 years ago

In 1998, scientists discovered that the expansion of the universe has been accelerating.

Lynna [10]

Dang that’s a cool fact bro

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3 years ago

Read 2 more answers

A quantity of gas has a volume of 0.20 cubic meter and an absolute temperature of 333 degrees kelvin. When the temperature of th

Nesterboy [21]

Answer:

Option C is the correct answer.

Explanation:

By Charles's law we have

V ∝ T

That is

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

Here given that

V₁ = 0.20 cubic meter

T₁ = 333 K

T₂ = 533 K

Substituting

$\frac{V_1}{T_1}=\frac{V_2}{T_2}\\\\\frac{0.20}{333}=\frac{V_2}{533}\\\\V_2=\frac{0.20}{333}\times 533=0.3198m^3$

New volume of the gas = 0.3198 m³

Option C is the correct answer.

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4 years ago

Explain why the temperature varies with distance from the Sun in this way?

GenaCL600 [577]

Answer:

The average surface temperature decreases the further you get from the Sun because the more distant planets receive less energy/heat/sunlight per square meter of their surface. This is because the energy from the Sun spreads out (becomes less concentrated) as you travel further from the source/Sun.

Explanation:

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3 years ago