1: Sandy purchases a dishwasher for R6500 on a hire purchase agreement. The agreement is that the loan is to be paid off over a
1 answer:
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Answer:
a)
b)
So the calculated value is 0.9 points above the actual value.
%
And the calculated value it's 0.537% higher than the actual value.
c) For this case we can use the slope obtained from the linear model to answer this question, and we can conclude that the CPI is increasing at approximate 3.8 units per year.
Step-by-step explanation:
Data given
1982 , CPI=100
1986, CPI = 191.2
Notation
Let CPI the dependent variable y. And the time th independent variable x.
For this case we want to adjust a linear model givn by the following expression:
Solution to the problem
Part a
For this case we can find the slope with the following formula:
And if we replace we got:
Let X represent the number of years after. Then for 1982 t = 0, and if we replace we can find b:
And then
So then our linear model is given by:
Part b
For this case we need to find the years since 1982 and we got x = 2000-1982=18, and if we rpelace this into our linear model we got:
And the actual value is 167.5 we can compare the result using absolute change or relative change like this:
So the calculated value is 0.9 points above the actual value.
And we can find also the relative change like this:
And if we replace we got:
%
And the calculated value it's 0.537% higher than the actual value.
Part c
For this case we can use the slope obtained from the linear model to answer this question, and we can conclude that the CPI is increasing at approximate 3.8 units per year.
Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:
The probability of both failing the test and being unfit is:
Hence, the conditional probability is:
0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287
Answer:
$57,500
Step-by-step explanation:
$57,500