Answer:
count me in
Step-by-step explanation:
Answer:
t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))
Step-by-step explanation:
Solve for t:
z = (h t^2)/2 + t q_1
z = (h t^2)/2 + t q_1 is equivalent to (h t^2)/2 + t q_1 = z:
(h t^2)/2 + t q_1 = z
Divide both sides by h/2:
t^2 + (2 t q_1)/h = (2 z)/h
Add q_1^2/h^2 to both sides:
t^2 + (2 t q_1)/h + q_1^2/h^2 = (2 z)/h + q_1^2/h^2
Write the left hand side as a square:
(t + q_1/h)^2 = (2 z)/h + q_1^2/h^2
Take the square root of both sides:
t + q_1/h = sqrt((2 z)/h + q_1^2/h^2) or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)
Subtract q_1/h from both sides:
t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t + q_1/h = -sqrt((2 z)/h + q_1^2/h^2)
Subtract q_1/h from both sides:
Answer: t = sqrt((2 z)/h + ((q_1)^2)/(h^2)) - q_1/h or t = -q_1/h - sqrt((2 z)/h + ((q_1)^2)/(h^2))
Answer:
The probability is 0.5086
Step-by-step explanation:
The probability P that at least one of these three modules will fail to work properly is calculated as:
P = 1 - P'
Where P' is the probability that all the modules works properly. So, P' os calculated as:
P' = 0.9 * 0.84 * 0.65
P' = 0.4914
Because 0.9 is the probability that module 1 works properly, 0.84 is the probability that module 2 works properly and 0.65 is the probability that module 3 works properly.
Finally, the probability P that at least one of these three modules will fail to work properly is:
P = 1 - 0.4914
P = 0.5086
