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JulsSmile [24]
2 years ago
15

Find the nth taylor polynomial for the function, centered at c. f(x) = ln(x), n = 4, c = 5

Mathematics
1 answer:
masha68 [24]2 years ago
3 0

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Given:

f(x) = ln(x)

n = 4

c = 3

nth Taylor polynomial for the function, centered at c

The Taylor series for f(x) = ln x centered at 5 is:

P_{n}(x)=f(c)+\frac{f^{'} (c)}{1!}(x-c)+  \frac{f^{''} (c)}{2!}(x-c)^{2} +\frac{f^{'''} (c)}{3!}(x-c)^{3}+.....+\frac{f^{n} (c)}{n!}(x-c)^{n}

Since, c = 5 so,

P_{4}(x)=f(5)+\frac{f^{'} (5)}{1!}(x-5)+  \frac{f^{''} (5)}{2!}(x-5)^{2} +\frac{f^{'''} (5)}{3!}(x-5)^{3}+.....+\frac{f^{n} (5)}{n!}(x-5)^{n}

Now

f(5) = ln 5

f'(x) = 1/x ⇒ f'(5) = 1/5

f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25

f'''(x) = 2/x³  ⇒ f'''(5) = 2/5³ = 2/125

f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625

So Taylor polynomial for n = 4 is:

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Hence,

The nth taylor polynomial for the given function is

P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴

Find out more information about nth taylor polynomial here

brainly.com/question/28196765

#SPJ4

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Tom and Jimmy plan to leave at the same time from home and
raketka [301]

To find the distance between the homes of Tom and Jimmy, it is assumed

that the distances from their home to the café are equal.

  • The distance between Tom and Jimmy's home is \underline{1,617.\overline 7 \ meters}<u />

Reasons:

The direction in which Tom and Jimmy walks = Towards each other

The speed at which Tom walks = 52 meters per minute

The speed with which Jimmy walks = 70 meters per minute

The time at which Tom leaves = 4 minutes earlier than Jimmy

The point at which they meet = The café

The rate of their speed = Constant

Required:

The distance between Tom and Jimmy home.

Solution:

Tom and Jimmy had a plan to walk at the same speed and meet up at the café.

We have;

The café is equal distance from Tom and Jimmy's houses.

Which gives the following simultaneous equation.

52 × (4 + t) = The distance of Tom's house from the café

70 × t = The distance of Jimmy's  house from the café

  • 52 × (4 + t) = 70 × t

52 × 4 = 70 × t - 52 × t = 18 × t

\displaystyle t = \frac{52 \times 4}{18}  = \frac{104}{9} = 11.\overline{6}

The time it take Jimmy to reach the café, <em>t</em> = \mathbf{11.\overline6} minutes

The distance between their homes, d = 52 × (4 + t) + 70 × t

∴ d = 52 × (4 + 11.\overline6) + 70 × 11.\overline6 = 1,617.\mathbf{\overline 7}

  • The distance between Tom and Jimmy's home = 1,617.\overline 7 meters

Learn more about simultaneous equations here:

brainly.com/question/12413726

6 0
2 years ago
How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
2 years ago
Question:
Scorpion4ik [409]

Answer:

substituting  & graphing

Step-by-step explanation:

4 0
2 years ago
What is the area of a parallelogram that has a base of 12 3/4 in. and a height of 2 1/2 in.?
EleoNora [17]
The area would be 24 inches
4 0
3 years ago
Solve,justify and check: 3(7+5n)=6n+6(1+4n)
vlabodo [156]

Answer:

1=n

Step-by-step explanation:

Step 1- Distribute into the parenthesis.

7(3)+5(3)n= 6n+1(6)+4(6)n

Step 2- Multiply

21+15n= 6n+6+24n

Step 3- Add common variables to simplify.

21+15n= (24n+6n)+6

21+15n= 30n+6

Step 4- Subtract the smallest variable to both sides.

21+15n= 30n+6

   -15n  -15n

21= 15n+6

Step 5- Subtract 6 to both sides.

21= 15n+6

-6           -6

15= 15n

Step 6- Divide both sides by 15.

<u>15</u>= <u>15n</u>

15   15

1=n

4 0
3 years ago
Read 2 more answers
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