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vovangra [49]
2 years ago
12

Write 2 / 3 of 4 as a mixed number. ​

Mathematics
2 answers:
elena-s [515]2 years ago
5 0
2/3 of 4 as a mixed number will be 2 2/3
timofeeve [1]2 years ago
5 0

Answer:

2 and 2/3

Step-by-step explanation:

i used my math skillz

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sveticcg [70]
5. y = x + 7
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4 0
2 years ago
A pair of fair dice is cast. Let Edenote the event that the number landing uppermost on the first die is a 1 and let Fdenote the
iris [78.8K]

Answer:

They are not independent

Step-by-step explanation:

Given

E = Occurrence of 1 on first die

F = Sum of the uppermost occurrence in both die is 5

Required

Are E and F independent

First, we need to list the sample space of a roll of a die

Event\ 1 = \{1,2,3,4,5,6\}

Next, we list out the sample space of F

Event\ 2 = \{2,3,4,5,6,7,3,4,5,6,7,8,4,5,\

6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12\}

In (1): the sample space of E is:

E = \{1\}

So:

P(E) = \frac{n(E)}{n(Event\ 1)}

P(E) = \frac{1}{6}

In (2): the sample space of F is:

F = \{5,5,5,5\}

So:

P(F) = \frac{n(F)}{n(Event\ 2)}

P(F) =\frac{4}{36}

P(F) =\frac{1}{9}

For E and F to be independent:

P(E\ and\ F) = P(E) * P(F)

Substitute values for P(E) and P(F)

This gives:

P(E\ and\ F) = \frac{1}{6} * \frac{1}{9}

P(E\ and\ F) = \frac{1}{54}

However, the actual value of P(E and F) is 0.

This is so because E = \{1\} and F = \{5,5,5,5\} have 0 common elements:

So:

P(E\ and\ F) = 0

Compare P(E\ and\ F) = \frac{1}{54} and P(E\ and\ F) = 0.

These values are not equal.

Hence: the two events are not independent

6 0
3 years ago
Super easy to get pointsss!!! HELPPPP
jeyben [28]

Answer:

3x3x12= volume of large prism= 108

1x1x12= volume of hole= 12

(Volume of prism)-(volume of hole)= 96

Step-by-step explanation:

8 0
4 years ago
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What is 8 minus 2.5 and explain how u got your answer.
Bess [88]
8-2.5 is 5.5 because when you subtract 2 from 6 you get 6b and when you subtract .5 from 6 you get 5.5
8 0
3 years ago
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22. PLEASE HELP PLEASSSSSSEEEEEEEE
antiseptic1488 [7]

Answer:

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Step-by-step explanation:

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