5y+45=180
5y=135
y=135/5
y=27
Cosh (In 5) = 1/2(e^(-ln 5) + e^(ln 5)) = 1/2(1/5 + 5) = 1/2(26/5) = 13/5 =2.6
Answer:
We do not have the function g(x), but this can be solved in a trivial way.
The average rate of change in a interval is the slope over that interval, so the average rate of change of g(x) in the interval 1 < x < 5 is
p = (g(x2) - g(x1))/(x2 - x1) where x2 > x1
p = (g(5) - g(1))/(5 - 1) = (g(5) - g(1))/4
Now, suppose that i have the new equation h(x) = g(x) + x
the rate of change of this function, the average rate of change in the interval will be:
p' = (h(5) - h(1))/(5 - 1) = (g(5) + 5 - g(1) - 1)/4 = (g(5) - g(1))/4 + 4/4 = p +1
so p' > p
and the average rate of change of h(x) is bigger than the one of g(x) in the interval 1< x < 5
