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Vera_Pavlovna [14]
2 years ago
15

Determine the number of terms, n, given the geometric series 1 3 9 27 ... and sn=3280.

Mathematics
1 answer:
lina2011 [118]2 years ago
5 0

The number of terms, 'n' is 8

<h3 /><h3>How to determine the number of terms</h3>

Let's determine the common ratio;

common ratio, r = 3/1 = 3

The formula for sum of geometric series with 'r' greater than 1 is given as;  Sn = a( r^n - 1) / (r - 1)

n is unknown

Sn = 3280

Substitute the value

3280 = 1 ( 3^n - 1) / 3- 1

3280 = 3^n -1 /2

Cross multiply

3280 × 2 = 3^n - 1

6560 + 1 = 3^n

6561 = 3^n

This could be represented as;

3^8 = 3^n

like coefficient cancels out

n = 8

Thus, the number of terms, 'n' is 8

Learn more about geometric series here:

brainly.com/question/24643676

#SPJ1

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\dfrac{-2}{3} \div 2\dfrac{1}{4} = <br> 3<br> −2<br> ​ <br> ÷2 <br> 4<br> 1<br> ​
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Step-by-step explanation:

Given

\dfrac{-2}{3} \div 2\dfrac{1}{4} =

Required

Solve

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