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2 years ago

What is the solution for x in the equation? 9 - 10x2x+1-8x x = ?

Mathematics

1 answer:

LUCKY_DIMON [66]2 years ago

4 0

Answer:

-3x

Step-by-step explanation:

this is the answer I think

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In the right triangle shown, A= 30° and AB = 8.

zloy xaker [14]

Answer:

$BC=4\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

$sin(30^o)=\frac{BC}{AB}$ ----> by SOH (opposite side divided by the hypotenuse)

we have

$AB=8\ units\\\\sin(30^o)=\frac{1}{2}$

solve for BC

$BC=sin(30^o)(AB)$

substitute the values

$BC=(\frac{1}{2})(8)$

$BC=4\ units$

4 0

2 years ago

What is the value of the 4 in the number 17.884?<br>Write your answer as a fraction.

ikadub [295]

Answer:

4/1000

Step-by-step explanation:

the value of 4 is 0.004 which in fraction form is 4/1000

6 0

3 years ago

PLEASE HELP

Mice21 [21]

Answer:

$\frac{x + 11}{8} = - 3 \\ x + 11 = - 3 .8 \\ x = - 24 - 11 \\ x = - 33$

maaf jika salah

6 0

2 years ago

Read 2 more answers

Can you help me please??

dusya [7]

Answer:

y = $\frac{4}{5}x+\frac{54}{5}$

Step-by-step explanation:

Equation of a line has been given as,

$y=\frac{4}{5}x+\frac{3}{5}$

Here, slope of the line = $\frac{4}{5}$

y-intercept = $\frac{3}{5}$

"If the two lines are parallel, there slopes will be equal"

By this property slope of the parallel line to the given line will be equal.

Therefore, slope 'm' = $\frac{4}{5}$

Since, slope intercept form of a line is,

y = mx + b

Therefore, equation of the parallel line will be,

y = $\frac{4}{5}x+b$

Since, this line passes through a point (-6, 6),

6 = $\frac{4}{5}(-6)+b$

6 = $-\frac{24}{5}+b$

b = $6+\frac{24}{5}$

b = $\frac{30+24}{5}$

b = $\frac{54}{5}$

Equation of the parallel line will be,

y = $\frac{4}{5}x+\frac{54}{5}$

4 0

3 years ago

Zigmanuir [339]

Answer:

Ai. Arithmetic sequence

Aii. Tn = 5 + 7n

Bi. Geometric

Bii. Tn = 8 × 2ⁿ¯¹

Step-by-step explanation:

To successfully answer the questions given above, note the following:

1. If the sequence is Arithmetic, then:

2nd – 1st = 3rd – 2nd = common difference (d)

2. If the sequence is geometric, then,

2nd / 1st = 3rd / 2nd = common ratio (r)

3. A sequence can not be arithmetic geometric at the same time.

4. The nth term of arithmetic sequence is:

Tn = a + (n – 1)d

5. The nth term of geometric sequence is:

Tn = arⁿ¯¹

A. Sequence => 12, 19, 26

i. Determination of the type of sequence.

We'll begin by calculating the common difference

1st term = 12

2nd term = 19

3rd term = 26

Common difference (d) = 2nd – 1st

d = 19 – 12 = 7

d = 3rd – 2nd

d = 26 – 19 = 7

Since a common difference exist in the sequence, the sequence is arithmetic sequence.

ii. Determination of the nth term.

Common difference (d) = 7

1st term (a) = 12

nth term (Tn) =?

Tn = a + (n – 1)d

Tn = 12 + (n – 1)7

Tn = 12 + 7n – 7

Tn = 5 + 7n

B. Sequence => 8, 16, 32

Bi. Determination of the type of sequence.

Let us begin by calculating the common ratio.

1st term = 8

2nd term = 16

3rd term = 32

Common ratio (r) = 2nd / 1st

r = 16 / 8

r = 2

r = 3rd / 2nd

r = 32 / 16

r = 2

Since a common ratio exist in the sequence, the sequence is geometric.

Bii. Determination of the nth term.

Common ratio(r) = 2

1st term (a) = 8

nth term =?

Tn = arⁿ¯¹

Tn = 8 × 2ⁿ¯¹

8 0

2 years ago