Question

Graph the systems of equations. {2x+y=8−x+2y=6

Answer 1

Answer:

Given system of equations are :

1). 2x + y = 8

2). -x + 2y = 6

Finding the intercepts of the equation (1) :

2x + y = 8

when x = 0 the y = 8

when y = 0 then x = 4

points are : (0,8) and (4,0)

Finding the intercepts of the equation (2) :

-x + 2y = 6

when x = 0 the y = 3

when y = 0 then x = -6

points are : (0,3) and (-6,0)

Hence, the required graphs of the given system of equation is attached below :

Answer 2

Hi, I actually just took the test and got 100%

Remember: When plotting the points for this equation, make sure to always first plot the ones that correspond to the first linear equation, and then plot the ones that correspond to the second linear equation. 

The points on the line should be for the first linear equation, (4,0) and (8,0). I got this answer by first converting the linear equation, 2x+y=8 from standard form to slope-intercept form. To do this, I subtracted 2x from both sides of the equation. So now it reads as y=8-2x. After this step was completed, I then graphed my first linear equation.
The points on the line should be for the first linear equation, (2,4) and (6,6). 
I got this answer by first converting the linear equation, -x+2y=6 into slope-intercept form. To do this, I subtracted -x from both sides of the equation. Then I had to divide the 2 into both -x and 6. So now it reads as y= 6/2-x/2. After this step was completed, I then graphed my second and final linear equation.


I hope this helps!