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Leto [7]
2 years ago
12

A____consists of many users and their information.​

Computers and Technology
2 answers:
Oduvanchick [21]2 years ago
8 0

Answer:

Active Directory

Explanation:

grin007 [14]2 years ago
7 0

<u>Active Directory</u> consist of many users and their information.

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Editing and sorting the data file are steps performed during the ________ stage in the data processing cycle
yawa3891 [41]
<span>Editing and sorting the data file are steps performed during the data preparation stage in the data processing cycle.</span>
5 0
3 years ago
1. Encrypt this binary string into cipher text: 110000. Include in your answer the formula the
puteri [66]

Answer:

Encrypt this binary string into ciphertext: 110000. Include

in your answer the formula the decoder would use to decrypt your cipher text in the format (coded answer) x N mod (m) = Y

-Decrypt this ciphertext into a binary string: 106

Now that you can see how public and private keys work in a real-world scenario, please explains how it works for computers and internet communications in relation to cybersecurity.

Explanation: ……………..

6 0
3 years ago
Open a command prompt on PC1. Issue the command to display the IPv6 settings. Based on the output, would you expect PC1 to be ab
Strike441 [17]

Answer:

yes it can communicate with all interfaces on the router.

Explanation:

PC1 has the right default gateway and is using the link-local address on R1. All connected networks are on the routing table.

Netsh may be a Windows command wont to display and modify the network configuration of a currently running local or remote computer. These activities will tell you in how manny ways we can use the netsh command to configure IPv6 settings.

To use this command :

1. Open prompt .

2. Use ipconfig to display IP address information. Observe the  output whether IPv6 is enabled, you ought to see one or more IPv6 addresses. A typical Windows 7 computer features a Link-local IPv6 Address, an ISATAP tunnel adapter with media disconnected, and a Teredo tunnel adapter. Link-local addresses begin with fe80::/10. ISATAP addresses are specific link-local addresses.  

3. Type netsh interface ipv6 show interfaces and press Enter. note the output listing the interfaces on which IPv6 is enabled. Note that each one netsh parameters could also be abbreviated, as long because the abbreviation may be a unique parameter. netsh interface ipv6 show interfaces could also be entered as netsh  ipv6 sh i.

4. Type netsh interface ipv6 show addresses  Observe the results  of the interface IPv6 addresses.

5. Type netsh interface ipv6 show destinationcache and press Enter. Observe the output of recent IPv6 destinations.

6. Type netsh interface ipv6 show dnsservers and press Enter. Observe the results listing IPv6 DNS server settings.

7. Type netsh interface ipv6 show neighbors and press Enter. Observe the results listing IPv6 neighbors. this is often almost like the IPv4 ARP cache.

8. Type netsh interface ipv6 show route and press Enter. Observe the results listing IPv6 route information.

5 0
3 years ago
people illegally download music over the internet although it's free it it is still illegal what do you choose to do? why
kodGreya [7K]

Answer:

its A i just did that

Explanation:

4 0
3 years ago
Write an application named [LastName]_MultiplicationTable and create a method that prompts the user for an integer value, for ex
WITCHER [35]

Answer:

I did this in C# & Java

Explanation:

C#:

       public static void Main(string[] args)

       {

           int input = Convert.ToInt32(Console.ReadLine());

           Multiply(input);

       }

       public static int Multiply(int input)

       {

           int ans = 0;

           for(int i =1; i<=10; i++)

           {

               ans = i*input;

               Console.WriteLine(i + "*" + input + "=" + ans);

           }

           return ans;

       }

Java:

   public static void main(String[] args)

   {

       Scanner myObj = new Scanner(System.in);  

       int input = Integer.parseInt(myObj.nextLine());

       Multiply(input);

   }

   public static int Multiply(int input)

   {

       int ans = 0;

       for(int i =1; i<=10; i++)

           {

               ans = i*input;

               System.out.println(i + "*" + input + "=" + ans);

           }

       return ans;

   }

7 0
3 years ago
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