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dem82 [27]
3 years ago
13

The IBM nine-track tapes that became the industry standard for storage for three decades had several sizes , the most common bei

ng 2400 feet. The high density version stored data at 1600 bits/inch/track. If the whole tape (not including the parity track) could be used for data storage , how much raw data could one of these tapes hold?
Computers and Technology
1 answer:
sergey [27]3 years ago
3 0

Answer:

5 MB.

Explanation:

1 foot = 12 inches

2400/9=266.66 feet per track

1 track excluding, remaining 8 track =2400 - 266.66 = 2133.33 feet

so, space available to store data = 2133.33 feet

now, 2133.33 feet = 25600 inches

total data that can be stored = 25600 * 1600 = 40960000 bits

= 46080000/8 = 5120000 Bytes

= 5120000/1000000 = 5.12 MB = 5 MB (approx.)

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Bond [772]

Answer:

import java.util.Scanner;

public class PercentagePopulation {

public static void main(String[] args) {

 // 1. Create an object of the Scanner class

 // This will allow for user's inputs

 Scanner input = new Scanner(System.in);

 // 2. Create a prompt asking the user to enter the number of males

 System.out.println("Please enter the number of males");

 // 3. Receive the number entered by the user and store in an int

 // variable called  number_of_males.

 int number_of_males = input.nextInt();

 // 4. Create a prompt asking the user to enter the number of

               // females

 System.out.println("Please enter the number of females");

 // 5. Receive the number entered by the user and store in an int

 // variable  called, number_of_females

 int number_of_females = input.nextInt();

 // 6. Find the sum of the number of males and females

 // Store the result in an int variable called total.

 int total = number_of_males + number_of_females;

 // 7. Find the percentage of males by using the appropriate

 // formula.  Do a type-casting to allow for division in floating point

               // representation by prepending the number_of_males by (double)

 double percentagemales = (double) number_of_males / total * 100.0;

 // 8. Find the percentage of females by using the appropriate

 // formula.  Do a type casting to allow for division in floating point

               // representation by prepending the number_of_males by (double)

 double percentagefemales = (double) number_of_females / total * 100.0;

 // 9. Print out the results

 System.out.println("Percentage males : " + percentagemales + "%");

 System.out.println("Percentage females : " + percentagefemales + "%");

}

}

Explanation:

Please go through the comments in the code to give an explanation of the program. The source code file has also been added to this response. Please download it and go through it.

Download java
4 0
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