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Westkost [7]
1 year ago
8

Find the Area Of each circle.

Mathematics
1 answer:
Levart [38]1 year ago
5 0

The area of the circle A and B is 86.54 inches and 124.62 mm

According to the statement

we have given that the radius of the circle A and b and we have to find the area of the given circle.

So, we know that the

The area enclosed by a circle of radius r is πr².

So, For area of the circle

For condition A :

diameter = 10.5 inches

then radius = 5.25

Area = πr²

Area = 3.14*27.56

Area = 86.54 inches

Now, For condition B :

radius = 6.3 mm

Area = πr²

Area = 3.14*39.69

Area = 124.62mm

So, The area of the circle A and B is 86.54 inches and 124.62 mm

Learn more about area of the circle here

brainly.com/question/15673093

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a school has 2 computer labs.Each lab has 30 computers. A total of 6 computers in the school are not working. which experission
jasenka [17]

Answer:

30(2)-6

Step-by-step explanation:

30 computers in 2 labs minus the 6 broken computers.

3 0
3 years ago
Read 2 more answers
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
Nate Kaeding, the place kicker for the San Diego Chargers, has a score 120 so far this season. He has scored all his points on 1
Tomtit [17]
1*y+3*x=120
y=x+12
(x+12)+3x=120
 x= 27 he made 27 field goals and 39 extra point kicks<span />
7 0
3 years ago
The population of Chicago, Illinois, in 2003 was 2,869,121. The area of Chicago was 227.1 square miles. What was the average num
ValentinkaMS [17]

Answer:

12,633.7

Step-by-step explanation:

population of Chicago, in 2003 = 2,869,121

The area of Chicago = 227.1 square miles.

What was the average number of people living in 1 square mile?

Average number of people living in 1 square mile also refers to the population density of Chicago

Average number of people living in 1 square mile = Total population / total square miles

= 2,869,121 / 227.1

= 12633.734037868

Approximately

12,633.7

5 0
2 years ago
.Factor 20x2 + 68x - 160
saveliy_v [14]

Answer:

4(5x-8) (x+5)

Step-by-step explanation:

4(5x^2+17x-40)

4(5x-8) (x+5)

3 0
2 years ago
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