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Lelu [443]
1 year ago
10

In a plot of probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum

occurs
Mathematics
1 answer:
Lunna [17]1 year ago
6 0

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

<h3>What is an electron?</h3>
  • The electron is a subatomic particle with a negative one elementary charge electric charge.
  • Electrons are the first generation of the lepton particle family and are widely regarded as elementary particles due to the lack of known components or substructure.

Electron in the hydrogen:

  • Hydrogen has the simplest electron configuration to write because it just contains one electron.
  • There is essentially only one electron surrounding the Hydrogen nucleus.
  • Because hydrogen only has one electron, its configuration is 1s1.
  • The maximum occurs at a0, the first Bohr radius, in a plot showing the chance of finding the electron in the hydrogen ground state vs the distance from the nucleus.

Therefore, in a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs (A) at a0. the first Bohr radius.

Know more about electrons here:

brainly.com/question/860094

#SPJ4

The complete question is given below:

In a plot of the probability of finding the electron in the hydrogen ground state versus the distance from the nucleus, the maximum occurs:

A. at a0. the first Bohr radius

B. at slightly less than a0

C. at slightly more than a0

D. at 2 a0

E. at a0/2

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castortr0y [4]

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3) \sqrt{5}

4)5\sqrt{13}

Step-by-step explanation:

distance between two points:

d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}

we have:

3) (6, -2), (8, -3)

x_{1} = 6

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x_{2} = 8

y_{2} =-3

so we have:

d =\sqrt{(8-6)^{2}+ (-3-(-2))^{2}}\\\\d =\sqrt{(2)^{2}+ (-1)^{2}}\\\\d = \sqrt{4+ 1}\\\\d=\sqrt{5}

4) (7,-8), (-8, 2)

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d =\sqrt{(-8-7)^{2}+ (2-(-8))^{2}}\\\\d =\sqrt{(-15)^{2}+ (10)^{2}}\\\\d = \sqrt{225+ 100}\\\\d=\sqrt{325}\\\\d=5\sqrt{13}

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3 years ago
A right triangle has a hypotenuse with a length of 130 cm. One leg has a length of 100 cm. What is the length of the other leg o
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Answer:

B. √6900

Step-by-step explanation:

The square length of hypotenuse is equal to sum of square length of two legs let x  represent the other leg

130^2 = 100^2 + x^2

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6900 = x^2 find the root for both sides

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