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Rasek [7]
3 years ago
6

Simplify 36p^16q^12r^15 + 18p^10q^13r^11 + 72p^8q^16r^12

Mathematics
1 answer:
hram777 [196]3 years ago
6 0
The three terms are not like terms, so they cannot be added together.
The expression is simplified.
If you need to factor the expression, then the instructions should be factor the expression, not simplify.
You might be interested in
4/5 ÷ 7/6 + 2/7 ∙2 1/5
Aleksandr [31]
<h2>The value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} =\dfrac{8}{7}</h2>

Step-by-step explanation:

We have,

\dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5}

To find, the value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} = ?

∴ \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5}

=\dfrac{4}{5}\times \dfrac{6}{7} +\dfrac{2}{7}.\dfrac{8}{5}

=\dfrac{24}{35} +\dfrac{16}{35}

Taking LCM of denominator, we get

=\dfrac{24+16}{35}

=\dfrac{40}{35}

Dividing numerator and denominator by 5, we get

=\dfrac{8}{7}

∴ The value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} =\dfrac{8}{7}

Hence, the value of \dfrac{4}{5} ÷ \dfrac{7}{6} + \dfrac{2}{7}.2\dfrac{1}{5} is equal to \dfrac{8}{7} .

4 0
3 years ago
Letang Industrial Systems Company (LISC) is trying to decide between two different conveyor belt systems. System A costs $280,00
Vanyuwa [196]

We have to calculate the EAC for both the conveyor belt system.

Solutions :

<u>Equivalent Annual Cost or (EAC) for the SYSTEM-A</u>

$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $tax rate )

                                $=-855,000(1-0.23)+\left[\left(\frac{280,000}{4}\right)\times 0.23\right]$

                               $= (-85,000 \times 0.77 ) + (70,000 \times 0.23)$

                               = $ 49,350

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -49,350                  0.909091                          -44,863.64

2                  -49,350                   0.826446                          -40,785.12

3                   -49,350                  0.751315                            -37,077.39

4                   -49,350                 <u> 0.683013   </u>                       <u>-33,706.71  </u>

     Total                                    $ 3.169865                       $ -156,432.86  

Therefore, Net Present value = present value of the annual cash flow - initial investment.

           = 156,432.86 - 280,000

          = $ 436,432.86 (negative)

Now the EAC or the Equivalent Annual Cost for System A :

$\text{EAC}= \text{Net present value / (PVIFA 10 percent, 4 years)}$

        $=\frac{436,432.86}{3.169865}$

        $= 137,681.86 $ dollar (negative)

$\text{Operating cash flow } = \text{Pre-tax annual operating cost (1-tax rate )} + (\text{depreciation expense} \times $tax rate)

$=79,000(1-0.23)+\left[\left(\frac{360,000}{6}\right) \times 0.23\right]$

$=(-78,000 \times 0.77)+(60,000 \times 0.23)$

= -$ 47,030

Year      Annual Cost flow     Present value factor    Present Value of Annual

                                                     at 10%                              cash flow

1                    -47,030                  0.909091                          -42,754.55

2                  -47,030                   0.826446                          -38,867.77

3                   -47,030                  0.751315                           -35,334.34

4                   -47,030                 0.683013                            -32,122.12

5                  -47,030                  0.620921                            -29,201.93

6                  -47,030                 <u> 0.564474  </u>                        <u>  -26,547.21 </u>  

    Total                                     $ 4.355261                       $  -204,827.91

Net Present Value = Present Value of annual cash inflows – Initial Investment

$= 204,827.91 - 360,000$

= -$ 564,827.91 (negative)

EAC for system B:

Equivalent Annual Cost for system B $=\frac{\text{net present value}}{\text{PVIFA 10 \text percent, 6 years}}$

$=\frac{-564,827.91}{4.355261}$

= -$129,688.66 (negative)

7 0
2 years ago
Which constant term would mean that the expression is completely factored? x2 – 3x
kolbaska11 [484]
Factor x2−3x−10x2−3x−10=(x+2)(x−5) Answer: (x+2)(x−5)

have a nice day !!!
7 0
2 years ago
3
liubo4ka [24]

Answer:

<h3>The answer is option D.</h3><h3 /><h3>3</h3>

Step-by-step explanation:

From the table above f(-2) = 3

Hope this helps you

4 0
3 years ago
I NEED HELP ASAP PLZZZZ LOOK AT THE PIC
umka2103 [35]

Answer:

The red line is g(x)

Step-by-step explanation:

* To solve this problem you must to know some fact about

  transformation

- If the function f(x) translated horizontally to the left  

 by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up  

 by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down  

 by k units, then the new function g(x) = f(x) – k

- A vertical stretching is the stretching of the graph away from

 the x-axis

• if k > 1, the graph of y = k•f (x) is the graph of f (x) vertically

 stretched by multiplying each of its y-coordinates by k.

- A vertical compression is the squeezing of the graph toward

 the x-axis.

• if 0 < k < 1 (a fraction), the graph is f (x) vertically compressed

 by multiplying each of its y-coordinates by k.

• if k should be negative, the vertical stretch or compress is

 followed by a reflection across the x-axis.  

* Now lets solve the problem

- g(x) = -1/2f(x + 2)

# x + 2 ⇒ means the graph moved 2 units to the left

# -1/2 ⇒ means the graph has vertical compressed followed

 by a reflection across the x-axis, then multiply

 each y-coordinate by -1/2

- The graph of f(x) intersects x-axis at point (3 , 0)

∴ The point will be (1 , 0) on g(x)

- The graph of f(x) intersects y-axis at point (0 , -6)

∴ The point will be (-2 , 3) on g(x)

* Look to the graph

# The red line is g(x)

# The blue line is f(x)

- To check your answer

# The equation of f(x) is f(x) = 2x - 6

∵ g(x) = -1/2f(x + 2)

∴ g(x) = -1/2[2(x + 2) - 6] = -1/2[2x + 4 - 6] = -1/2[2x - 2] = -x + 1

* g(x) intersect x-axis at point (1 , 0) and y-axis at point (0 , 1)

3 0
3 years ago
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