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dimaraw [331]
2 years ago
14

The highway mileage (mpg) for a sample of 8 different models of a car company can be found below. Find the mean, median, mode, a

nd standard deviation. Round to one decimal place as needed.
19, 22, 26, 27, 30, 32, 35, 35

Mean =


Median =


Mode =


Standard Deviation =
Mathematics
1 answer:
denis-greek [22]2 years ago
5 0

The mean of the samples is 28.25.

The median of the samples is 28.5

The mode of the samples is 35

The standard deviation of the samples is 5.47.

<h3>Mean of the data points</h3>

The mean for highway mileage (mpg) for a sample of 8 different models of a car company is calculated as follows;

mean = (19 + 22, 26, 27, 30, 32, 35, 35)/8

mean = 28.25

<h3>Median of the data points</h3>

The median is calculated as;

median = (27 + 30)/2 = 28.5

<h3>Mode of the data points</h3>

mode = 35 (it has the highest frequency)

<h3>Standard deviation</h3>

∑(x - x')² = (19 - 28.25)²  +  (22 - 28.25)² + (26 - 28.25)² + (27 - 28.25)² + (30 - 28.25)²  + (32 - 28.25)² + (35 - 28.25)² + (35 - 28.25)²

∑(x - x')² = 239.5

S.D = √[(∑(x - x')² / N]

S.D = √(239.5/8)

S.D = 5.47

Learn more about standard deviation here: brainly.com/question/475676

#SPJ1

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The first eight quizzes in this class had average scores of 8,9,9,8,8,9,8,7. This gives a sample mean of 8.25 and a sample stand
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Answer:

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }  

            t = <em>1.076</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given Mean of the Population (μ) = 8.0

<em>Mean of the sample (x⁻) = 8.25</em>

Given data

                  8,9,9,8,8,9,8,7

Given sample size  n= 8

Given sample standard deviation(S) = 0.661

<u><em>Step(ii):-</em></u>

<em>Null hypothesis : H:  (μ) = 8.0</em>

<em>Alternative Hypothesis :H:(μ) > 8.0</em>

<em>Degrees of freedom = n-1 = 8-1=7</em>

<em>Test statistic </em>

<em>               </em>t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }<em></em>

<em>              </em>t = \frac{8.25 -8.0}{\frac{0.661}{\sqrt{8} } }<em></em>

<em>            t =  1.076</em>

<em>Critical value </em>

<em>                    t₍₇,₀.₀₅₎   = 2.3646</em>

<em>The calculated value   t =  1.076 < 2.3646 at 0.05 level of significance</em>

<em>Null hypothesis is accepted</em>

<em>Test the hypothesis that the true mean quiz score is 8.0 against the alternative that it is not greater than 8.0</em>

<em></em>

3 0
3 years ago
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