Question

A multiprocessor with 10 processors has 36 attached tape drives. A number of jobs have been submitted to the system where each job requires a maximum of 6 drives in order to complete execution. Assume that each job starts running with only 4 drives for a long period before requiring the other 2 drives for a short period toward the end of its operation. Also assume an endless supply of those jobs
Assume the scheduler in the operating system will not start a job unless there are 6
tape drives available. When a job is started, 6 drives are assigned immediately and
are not released until the job finishes.
1 What is the maximum number of jobs that can be in progress at once?
2 What is the maximum number of tape drives that may be left idle as a result of
this policy?
3 What is the minimum number of tape drives that may be left idle as a result of
this policy?

Answer 1

The maximum number of tape drivers that are required by each job in the multiprocessor is 6.

How to illustrate the information?

It is given that a job will be performed in parallel with 4 tape drivers and laterin series with remaining 2 tape drivers. The maximum number of jobs that cab be progress simultaneously will be:

= total number of tape drivers / number of tape drivers assigned for each job.

Maximum number of jobs that cab be progress simultaneously = 36 / 6 = 6

Each process run with 4 tape drivers parallel and remaining 2 tape drivers is used at the last. Therefore, most of the time the 4 tape drivers are used and the remaining 2 tape drivers is left idle.

The maximum number of tape drivers kept idle = last tape drive in each of the processes running.

There are 6 processes running so, the maximum number of processes left idle is 6.

When each process makes use of all the tape drivers, and then there will not be any idle state for the tape drivers. Therefore, the minimum number of tape drivers kept idle is 0.

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