Answer:
Option c is the correct answer for the above question.
Explanation:
- If the array will store in row-major order, then it will be a store like the first row, then second row and then third row.
- If the user wants to conclude the address of the A[3,5], then the address of the A[3,5] will be 184.
- It is because the 3 states the row number and the 5 states the column number.
- The above question states that every value take 8 bit. and there are 4 rows from 0 to 3 and 6 column (0 to 5) for every row (except the fourth rows because it takes 5 columns from 0 to 4) before the A[3,5].
- So there are 23 value before A[3,5] which are as-- [00,01,02,03,04,05][10,11,12,13,14,15][20,21,22,23,24,25][30,31,32,33,34].
- So when every value takes 8 bit then 23 value takes 184 bits(23*8).
- So the address of A[3,4] is 184.
- Hence option c is the correct and the other is not because of 184 stated from the c option only.
Human centered technology often recommends best practices to computer designers and manufacturers, ...............
Human-Computer Interaction is a study that particularly focuses more on the design of computer technology and the interaction between humans and computers. Since the 1980s when HCI surfaced, it has become a crucial tool in popularizing the idea that the interaction between a user and a computer should resemble a human-to-human, open-ended dialogue. When HCI is done well, a human-centered approach powers the creation of products that resonates more deeply with a certain audience. This will ultimately drive engagement and growth.
<u>Answer:</u>
I am writing <em>partial code in</em> <em>c++ to calculate weighted average</em>. The weighted average should be calculated based on multiplying the test score and its <em>respective weight and finally add all the test score.</em>
<u>Explanation:</u>
<em>int arrtestscore[100];</em>
<em>int arrweight[100];</em>
<em>int n;</em>
<em>double weightedavg;</em>
<em>cout<<”Enter the number of test score for which weighted average needs to be calculated”;</em>
<em>cin>>n;</em>
<em>for(int x = 0; x <n;x++)</em>
<em>{</em>
<em> cout<<”Enter test score :” + (x+1) ;</em>
<em> cin>>arrtestscore[x];</em>
<em> count<<”Enter the respective weight:”;</em>
<em> cin>>arrweight[x];</em>
<em>}</em>
<em>for (int i=0; i<n;i++)</em>
<em>{</em>
<em> weightedavg = weightedavg + (arrtestscore[i] * arrweight[i])</em>
<em>}</em>
<em>cout<<”weighted average = “ <<weightedavg; </em>
The options are missing from the question.
Below are the options.
A) 192.168.15.0
B) 192.168.15.16
C) 192.168.15.32
D) 192.168.15.64
Answer: The correct option to the question is option D
192.168.15.64
Explanation:
The Network is: 192.168.15.64/26 11000000.10101000.00001111.01000000
Then the Broadcast is: 192.168.15.127 11000000.10101000.00001111.01111111
We see the HostMin as: 192.168.15.65 11000000.10101000.00001111.01000001
And the HostMax as: 192.168.15.126 11000000.10101000.00001111.01111110
