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zhenek [66]
2 years ago
14

Solve for x in the following equation.

Mathematics
2 answers:
WARRIOR [948]2 years ago
5 0

\huge\text{Hey there!}


\mathsf{5^{x - 2} = 5^8}

\mathsf{5^{x - 2} = 5\times5\times5\times5\times5\times5\times5\times5}

\mathsf{5^{x - 2} = 25\times25\times25\times25}

\mathsf{5^{x - 2} = 625\times625}

\mathsf{5^{x - 2} =390,625}

\large\textsf{Solving for the exponent:}

\mathsf{5^{x - 2} =390,625}

\large\textsf{Take the log (logarithm) to both of the sides:}

\mathsf{log(5^{x - 2} \rightarrow  log(390,625)}

\large\textsf{Simplify it:}

\mathsf{(x - 2) \times(log (5)) \rightarrow log(390,625)}

\large\textsf{Simplify that as well:}

\mathsf{x - 2 = \dfrac{log(390,625)}{log(5)}}

\large\textsf{You get it: }\mathsf{x - 2 = 8}

\large\textsf{ADD by 2 to BOTH of the SIDES:}

\mathsf{x - 2 + 2 = 8 + 2}

\large\textsf{Simplify it:}

\mathsf{x = 8 + 2}

\mathsf{x = 10}


\huge\textsf{Therefore, your answer should be:}

\huge\boxed{\mathsf{x =} \frak{10}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

USPshnik [31]2 years ago
3 0

Answer:

\fbox{x=10}

Step-by-step explanation:

Given:

{5}^{x - 2}  =  {5}^{8}

<em>Since base of both the equivalent is same hence the exponent will also be equal to each other.</em>

Comparing the exponent of LHS & RHS,

x-2 =8

adding 2 on both the side,

x-2+2= 8+2

\fbox{x=10}

\small \sf Thanks \:  for  \: joining  \: brainly  \: community!

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