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Sliva [168]
3 years ago
5

Tori rolls three numbered 1 though 6. She records it weather each cube lands on an even or odd number

Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0

Answer:

480 times

Step-by-step explanation:

Given

n = 50 ---- total number of rolls

See attachment for complete question

Required

Times OO will appear in a roll of 2000 times

From the attached bar graph,

n(OO) = 12

So, the occurrence of OO in 2000 rolls is:

OO = \frac{n(OO)}{n} * 2000

OO = \frac{12}{50} * 2000

OO = 0.24 * 2000

OO = 480

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Solve for G<br><br> •1.00<br> •36.03<br> •90<br> •43.34<br> •46.66<br> •7.55
g100num [7]

Answer:42.98

Step-by-step explanation:

Hf=√(11^2-8^2)

Hf=√(121-64)

Hf=√(57)

Hf=7.5

11/sin90 =7.5/sinG

Sin90=1

11/1=7.5/sinG

Cross multiply

11 x sinG=7.5 x 1

11sinG=7.5

Divide both sides by 11

11sinG/11=7.5/11

sinG=0.6818

G=sin(inverse)(0.6818)

G=42.98

6 0
3 years ago
Simplify, following the order of operations: 5 102 – 3 × (12 – 8)
JulijaS [17]

5 + 10^2 - 3 ( 12 - 8 ) = 93 12 - 8 = 4 then do 3 x 4 which = 12 and then add 5 to 10^2 which = 105 105 - 12 = 93

5 0
2 years ago
Read 2 more answers
Factor completely x^8- 16.
Nataly_w [17]

Answer:

Step-by-step explanation:


So in this example we'll be using the difference of squares which essentially states that: (a-b)(a+b)=a^2-b^2 or another way to think of it would be: a-b=(\sqrt{a}-\sqrt{b})(\sqrt{a}+\sqrt{b}). So in this example you'll notice both terms are perfect squares. in fact x^n is a perfect square as long as n is even. This is because if it's even it can be split into two groups evenly for example, in this case we have x^8. so the square root is x^4 because you can split this up into (x * x * x * x) * (x * x * x * x) = x^8. Two groups with equal value multiplying to get x^8, that's what the square root is. So using these we can rewrite the equation as:

x^8-16 = (x^4-4)(x^4+4)

Now in this case you'll notice the degree is still even (it's 4) and the 4 is also a perfect square, and it's a difference of squares in one of the factors, so it can further be rewritten:

x^4-4 = (x^2-2)(x^2+2)

So completely factored form is: (x^2-2)(x^2+4)(x^4+4)

I'm assuming that's considered completely factored but you can technically factor it further. While the identity difference of squares technically only applies to difference of squares, it can also be used on the sum of squares, but you need to use imaginary numbers. Because x^2+4 = x^2-(-4). and in this case a=x^2 and b=-4. So rewriting it as the difference of squares becomes: x^4+4 = x^4 - (-4) = (x^2-\sqrt{-4})(x^2+\sqrt{-4}) = (x^2-2i)(x^2+2i) just something that might be useful in some cases.

7 0
1 year ago
Read 2 more answers
Inverse function of f(x)=e^(2x-1)
Len [333]
  f(x) = e²ˣ⁻¹
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3 years ago
*URGENT* which answer is a solution to the inequality?
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Try them and see.

For the first:
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7 0
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