Answer:
480 times
Step-by-step explanation:
Given
---- total number of rolls
See attachment for complete question
Required
Times OO will appear in a roll of 2000 times
From the attached bar graph,
So, the occurrence of OO in 2000 rolls is:
48
4/6 = 2/3
2/3 times 72 = 48
8/15
Using Pythagorean Theorem the length of XZ is 15.
tan X = opposite / adjacent = YZ / XZ = 8 / 15.