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Zarrin [17]
2 years ago
13

How can you put 33 people into different classes

Mathematics
1 answer:
nika2105 [10]2 years ago
8 0

Answer:

Yes

Step-by-step explanation:

This is already tough due to 33 being an odd number of people. And obviously, an amount of people can't be a decimal.

So in order to do this, simply divide 33/3 which is 11. This would mean there would be 3 people per classroom.

3 people in each of the 11 classrooms!

That's it, solved!

Thank you,

Eddie

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nasty-shy [4]

Answer:

The answer should be B

8 0
3 years ago
Jose takes 120 minutes to weed 6 equal rows of vegetable plants in his garden. What is his unit rate
Zarrin [17]

Answer:

3 rows/hour

Step-by-step explanation:

It is given that, Jose takes 120 minutes to weed 6 equal rows of vegetable plants in his garden.

120 minutes = 2 hours

We need to find the unit rate per hour for weeding these rows of his garden. It can be calculated as follows :

R=\dfrac{6}{2}\\\\R=3\ \text{rows/hour}

So, the rate for weeding these rows of his garden is 3 rows per hour.

6 0
3 years ago
What does the expression 12f<br> =24 represent?
Law Incorporation [45]
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6 0
3 years ago
Read 2 more answers
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les
kaheart [24]

Answer:

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation  

n=1000 represent the random sample taken    

\hat p=0.52 estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

\alpha=0.05 represent the significance level (no given, but is assumed)    

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

5 0
3 years ago
Explain how you decide wether to multiply or divide by 3 if you need to convert yards to feet.
Valentin [98]

Answer:

Step-by-step explanation:

Converting yards to feet means that we want the label of yards to cancel, leaving feet as our label. Use the factor-label method taught in chemistry.

???yds *\frac{3feet}{1yd}

The yards label cancels out, leaving feet as our label.  So to answer the question, in order to convert from yards to feet you are multiplying by 3.

6 0
3 years ago
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