Answer:
<em>A = 70</em>
Step-by-step explanation:
<em>CB </em>is equal to <em>EZ </em>and <em>E </em>equals 35, and <em>E </em>and <em>C </em>are the same, therefore, both <em>E </em>equals 35. Since there's 180 degrees in a triangle, and <em>ABY </em>equals 105, you have to subtract 180 - 105 to get the other angle. When you do that, you get that <em>B </em>equals 75. You have to add <em>E </em>and <em>B</em> (35 + 75), since that's in the same triangle as <em>A. </em>When you do that, you get 110. Subtract 180 - 110 to get <em>A, </em>which is 70.
Answer:
B- Parallelogram PQRS is also a rhombus.
Step-by-step explanation:
Given
Parallelogram PQRS with perpendicular diagonals
Required
Which of the option is true
(a) PQRS can be a rectangle
A rectangle do not have perpendicular diagonals.
Hence, (a) is false
<em>If (a) is false, then (d) is also false</em>
(b) PQRS can a rhombus
The diagonals of a rhombus are not perpendicular.
So (b) <em>is true</em>
<em>No need to check for (c), since only option is true</em>
Answer:
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Answer:
Following are the solution to this question:
Step-by-step explanation:
They provide various boxes or various objects. It also wants objects to be distributed into containers, so no container is empty. All we select k objects of r to keep no boxes empty, which (r C k) could be done. All such k artifacts can be placed in k containers, each of them in k! Forms. There will be remaining 
objects. All can be put in any of k boxes. Therefore, these objects could in the 
manner are organized. Consequently, both possible ways to do this are
Consequently, the number of ways that r objects in k different boxes can be arranged to make no book empty is every possible one
