All categories

2 years ago

assuming that no denominator equals zero, what is the simplest form of x+2/ x^2 +5x+6 divided by 3x+1/x^2-9

Mathematics

2 answers:

julia-pushkina [17]2 years ago

5 0

Definitely 8 because x+2/x^2 is 8

Alona [7]2 years ago

4 0

Answer:

Step-by-step explanation:

You might be interested in

Hector took out a small loan of $900 for 15 months. The simple interest rate on the loan was 15%. How much will he pay in intere

Liula [17]

So you have to find 15 percent of 900 which would be 135

3 0

3 years ago

The manager of a store that specializes in selling tea decides to experiment with a new blend. She will mix some Earl Grey tea t

marishachu [46]

Let us say that:

x = mass from Earl Grey Tea

y = mass from Orange Pekoe Tea

So that:

x + y = 600

and that:

6 x + 4 y = 4.5 * 600

6 (600 – y) + 4 y = 2700

3600 – 6y + 4y = 2700

-2y = -900

y = 450 pounds

x = 600 – 450 = 150 pounds

Answer:

Earl Grey Tea = 150 pounds

Orange Pekoe Tea = 450 pounds

4 0

4 years ago

If a+b = 7, and a² +b²=25 then ab = ?

Rama09 [41]

a2+b2=25

or, (a+b)^2-2ab=25

or, (7)^2-2ab=25 [a+b=7]

or, 49-25=2ab

or, 24/2=an

•°• ab=12....

3 0

3 years ago

Please solve this (Rational numbers 8th grade)

pochemuha

Question # 1

Answer:

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Step-by-step explanation:

Given the expression

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$

$=-\frac{2}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}$ ∵ $\frac{-2}{3}\times \frac{3}{5}=-\frac{2}{5}$

$=-\frac{2}{5}+\frac{1}{4}$ ∵ $\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=\frac{1}{4}$

$\mathrm{Least\:Common\:Multiplier\:of\:}5,\:4:\quad 20$

$=-\frac{8}{20}+\frac{5}{20}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-8+5}{20}$

$\mathrm{Add/Subtract\:the\:numbers:}\:-8+5=-3$

$=\frac{-3}{20}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{3}{20}$

Therefore,

$\frac{-2}{3}\times \frac{3}{5}+\frac{5}{2}\times \frac{3}{5}\times \frac{1}{6}=-\frac{3}{20}$

Question # 2

Answer:

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

Step-by-step explanation:

Given

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}$

$=-\frac{6}{35}-\frac{1}{6}\times \frac{3}{2}\times \frac{2}{5}\times \frac{1}{14}$ ∵ $\frac{2}{5}\times \frac{-3}{7}=-\frac{6}{35}$

$=-\frac{6}{35}-\frac{1}{140}$ ∵ $\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=\frac{1}{140}$

$\mathrm{Least\:Common\:Multiplier\:of\:}35,\:140:\quad 140$

$=-\frac{24}{140}-\frac{1}{140}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{-24-1}{140}$

$\mathrm{Subtract\:the\:numbers:}\:-24-1=-25$

$=\frac{-25}{140}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=-\frac{25}{140}$

$\mathrm{Cancel\:the\:common\:factor:}\:5$

$=-\frac{5}{28}$

Therefore,

$\frac{2}{5}\times \frac{-3}{7}-\frac{1}{6}\times \frac{3}{2}\times \frac{1}{14}\times \frac{2}{5}=-\frac{5}{28}$

4 0

4 years ago

Find the value of each expression. Show your work.

Verdich [7]

Answer:

$A) (1.2)^{2} = 1.44$

$B)2^ 3+17-(3\times 4) = 13$

$C)\frac{(9)^2}{(3)^3} = 3$

Step-by-step explanation:

Here, the given expressions are:

A) $(1.2)^{2}$

Solving this, we get

$(1.2)^{2} = 1.2 \times 1.2 = 1.44$

⇒ $(1.2)^{2} = 1.44$

B) $2^ 3+17-(3\times 4)$

Now, solving this, we get

$2^ 3+17-(3\times 4) = (2 \times 2 \times2) + (17 -12)\\=8 + 5 = 13$

⇒ $2^ 3+17-(3\times 4) = 13$

C) $\frac{(9)^2}{(3)^3}$

Simplifying this, we get

$\frac{(9)^2}{(3)^3} = \frac{(9\times9)}{(3 \times 3\times3)} = 3$

⇒ $\frac{(9)^2}{(3)^3} = 3$

4 0

3 years ago