Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
Answer:
3. The first equation can be multiplied by 3 and the second equation by 2.
Step-by-step explanation:
2 x + 3 y = 25 (1)
-3 x + 4 y = 22 (2)
Multiply equation (1) by 3 and (2) by 2.
3(2x) = 6x
2(-3x) = -6x
When you add the two equations, x will get cancelled last
It would need to be 16.4592 meters higher which rounds to 16 meters rounded to the nearest tenth
I think it’s 1/5 simplified
