
Write 1 2/3 as an improper fraction...
1 = 3/3. Plus the 2/3 makes 5/3.

To add/subtract fractions, they need the same denominator. (bottom number)
We can change the denominator by multiplying the top and bottom of a fraction by the same number. (it will stay equal, like 1/2 and 2/4)
Let's change 5/3 and 3/4 to a denominator of 12.
5/3 = 20/12 (bottom multiplies by 4, so does the top)
3/4 = 9/12 (bottom multiplies by 3, so does the top)

Now we just subtract the 20 minus 9 twelfths. (the twelfths act as a sort of unit)
4.4
Not sure if I'm right but I think it's 4.4. If I'm wrong I'm sorry, if someone can tell me if ik right that would be great. <3
Answer:
B 45 degrees
Step-by-step explanation:
if AB and CA are = the M2 = 90 degrees
in an right triangle ware one angle is 90 degrees and one is 45 degrees the outer one will be 45 degrees
the total of the angles in a triangle is 180 degrees so 180 - 90 = 90
90 - 45 = 45
so the remaining angle is 45.
Given that the AC and BC are perpendicular, their slopes are the negative inverse of each other which gives that the product of the slopes of AC and BC is -1
<h3>How can the prove that the product of the slopes is -1 be found?</h3>
The completed proof is presented as follows;
The slope of AC or GC is GF/FC by definition of slope. The slope of BC or CE is DE/CD by definition of slope.
<FCD = <FCG + <GCE + <ECD <u>by angle addition property </u> <FCD = 180° by the definition of a straight angle, and <GCE = 90° by definition of perpendicular lines. So by substitution property of equality 180° = <FCG + 90° + <ECD. Therefore 90° - <FCG = <ECD, by the <u>subtraction property of equality </u> . We also know that 180° = <FCG + 90° + <CGF by the triangle sum theorem and by the subtraction property of equality 90° - <FCG = <CGF, therefore <ECD = <CGF by the substitution property of equality. Then <ECD ≈ <CGF by the definition of congruent angles. <GFC ≈ <CDE because all right angles are congruent. So by AA ∆GFC ~ ∆CDE. Since <u>the ratio of corresponding sides of similar triangles are equal</u> then GF/CD = FC/DE or GF•DE = CD•FC by cross product. Finally, by the division property of equality GF/FC = CD/DE. We can multiply both sides using the slope of using the <u>multiplication property of equality </u> to get GF/FC × -DE/CD = CD/DE × -DE/CD. Simplify so that GF/FC × -DE/CD = -1. This shows that the product of the slopes of AC and BC is -1.
Learn more about perpendicular lines here:
brainly.com/question/20475360
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Answer:
-10
Step-by-step explanation:
3x^2 - 2(3y + 2x)
3(-2)^2 - 2(3(5) + 2(-2))
3*4 -2( 15-4)
12 -2(11)
12-22
-10