White blood cells also called leukocytes are the cells that help fight infection causing protection of the body against a disease or foreign substance. An example is a leukemia which then creates a large number of abnormal white blood cells.
The mutation in the sperm cell could be passed on to offspring, while the skin cell mutation could only affect the individual.
First, write out all combinations for the parents:
<u>SsBB</u>:
SB
sB
SB
sB
<u>ssBb</u>:
sB
sb
sB
sb
So now that you know what to put on as the x and y for the Punnett Square, set it up:
<u> | SB | sB | SB | sB </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
Now, listing each possible genotype and the number of times they show up in the square:
SSBB
0 times
SSBb/SSbB
0 times
SSbb
0 times
SsBB/sSBB
4 times
SsBb/SsbB/sSBb/sSbB/
4 times
Ssbb/sSbb
0 times
ssBB
4 times
ssBb/ssbB
4 times
ssbb
0 times
Since there are only 4 genotypes are possible, set up ratios of those four:
SsBB:
4 times/16 total = .25 = 25%
SsBb:
4 times/16 total = .25 = 25%
ssBB:
4 times/16 total = .25 = 25%
ssBb:
4 times/16 total = .25 = 25%
This means that the<em> genotypes</em> have a 25% : 25% : 25% : 25% likelihood.
Now, let's figure out the phenotypes of the 4 genotypes:
SsBB:
Ss = dominant
BB = dominant
SsBb:
Ss = dominant
BB = dominant
ssBB:
ss = recessive
BB = dominant
ssBb:
ss = recessive
Bb = dominant
So we have 2/4 that are S-dominant B-dominant and 2/4 that are S-recessive B-dominant.
This means that the phenotypes are:
2/4 = 50% Thin stripes with black eyes, and
2/4 = 50% Thin stripes with gray eyes.
I hope this helped you out :)