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BaLLatris [955]
1 year ago
6

A hairdresser is making 2 hair bows. She needs 9 over 10 yards for each bow. If she has 4 and 1 over 6 yards of ribbon, how much

will be left over after making the bows?
thirteen over ten yards
one and one over twelve yards
two and eleven over thirty yards
2 and twenty-nine over thirty yards
Mathematics
1 answer:
trasher [3.6K]1 year ago
8 0

The ribbon leftover will be (2 + 11/30)yd, so the correct option is the third one.

<h3>How much will she have left after making the bows?</h3>

We know that she wants to make 2 bows, where each bow needs 9/10 yards of ribbon, so for the two bows she needs:

2*(9/10) yd = 18/10 yd.

Now, the total amount of ribbon that she has is:

T = (4 + 1/6) yd = (24/6 + 1/6) yd = (25/6) yd

To see how much she will have left, we just need to take the difference between these two fractions:

Leftover = (25/6) yd -  18/10 yd.

we can use 30 as a common denominator, then we rewrite:

Leftover =  (125/30) yd - (54/30)yd = 71/30yd

Now we can rewrite:

Leftover = 71/30 yd = 60/30 yd + 11/30 yd = (2 + 11/30)yd

The correct option is the third one.

If you want to learn more about fractions:

brainly.com/question/11562149

#SPJ1

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Answer: Bonnie can make 40 treat bags. Each treat bag has three pieces of Candy A, 11 pieces of Candy B, and 13 pieces of Candy C.

Step-by-step explanation:

Since there's no number of student's in her child's class, I did this:

I found the common factors of 120, 440, and 520. And found out that the GCF (greatest common factor) is 40.

120: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120.

440: 1, 2, 4, 5, 8, 10, 11, 20, 22, 40, 44, 55, 88, 110, 220, 440.

520: 1, 2, 4, 5, 8, 10, 13, 20, 26, 40, 52, 65, 104, 130, 260, 520.

After finding out that the GCF is 40, I took the numbers 120, 440, and 520, and divided them by 40.

120 divided by 40 = 3

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