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Amiraneli [1.4K]
3 years ago
7

Question 5 of 5 0 3 4 5 6 7 8 9 10 Which of the following could be the number shown on the number line? O A A. V20 OB. √24 C. 27

D. 26​
Mathematics
2 answers:
8_murik_8 [283]3 years ago
6 0

Answer:

hi may u send a pic?

Step-by-step explanation:

viktelen [127]3 years ago
5 0

Answer: 24

Step-by-step explanation:

With every number starting with 2 count the number line up it doesn't past 5 or on 5 so it's not 5. It's past 4 so whats your answer?

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Each of the teams in a mixed volleyball league consists of 5 men and 5 women. there are 9 men and 10 women, including julia, who
IRISSAK [1]

Using the combination formula, it is found that 15,876 teams would include Julia.

The order in which the people are chosen to the team is not important, hence the combination formula is used to solve this question.

<h3>What is the combination formula?</h3>

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by:

C_{n,x} = \frac{n!}{x!(n-x)!}

In this problem:

  • 5 men are chosen from a set of 9.
  • 4 women are chosen from a set of 9(as Julia is already on the team).

Hence the number of teams is given by:

C_{9,5} \times C_{9,4} = \frac{9!}{5!4!} \times \frac{9!}{5!4!} = 15876

More can be learned about the combination formula at brainly.com/question/25821700

#SPJ1

8 0
2 years ago
Help. Please open powerpoint and help me!
GREYUIT [131]

Answer:

<u>3</u><u>0</u><u>.</u><u>4</u><u>%</u><u> </u>

1000 at £1.10

1000 x 1.10 = £1100

35% of 1000 is given away

1000 - 35% = 1000 - 350 = 650 left

35% of £1100 = £385, subtract to get £715 pounds worth of pins left

650 are left, with 385 pounds lost

60% of 650 = 390 pins sold at £3 each

40% of 650 = 260 sold at £5 for 2

3 x 390 = £1170 made from the first lot

260/2 = 130 x 5 = £650 made from the second lot

£1170 + £650 = £1820 from sales

Sales - cost to make - losses (giveaways) = profit value

1820 - 1100 - 385 = 335 pounds of profit

To find the gross profit margin, we take the profit, and find what percentage of the production cost it is.

335 is about 30.45% of 1100

30.45%, which is 30.4% to 1 decimal place.

The user is not responsible for any errors and all care should be taken to validate answer by self before submission.

7 0
3 years ago
The four cities on the map below form a square. About how many miles is the most direct route from Washington to Springfield?
natali 33 [55]

Answer:

Step-by-step explanation:100 miles down the middle when you do pythagorean thearom.

8 0
3 years ago
Read 2 more answers
Sid had $42 he owned $10 to his brother .Choose the correct expression to show this
Dafna11 [192]

Answer:

B. 42-10

Step-by-step explanation:

It is the amount that Sid has minus what he ows

7 0
3 years ago
Read 2 more answers
The life of a red bulb used in a traffic signal can be modeled using an exponential distribution with an average life of 24 mont
BartSMP [9]

Answer:

See steps below

Step-by-step explanation:

Let X be the random variable that measures the lifespan of a bulb.

If the random variable X is exponentially distributed and X has an average value of 24 month, then its probability density function is

\bf f(x)=\frac{1}{24}e^{-x/24}\;(x\geq 0)

and its cumulative distribution function (CDF) is

\bf P(X\leq t)=\int_{0}^{t} f(x)dx=1-e^{-t/24}

• What is probability that the red bulb will need to be replaced at the first inspection?

The probability that the bulb fails the first year is

\bf P(X\leq 12)=1-e^{-12/24}=1-e^{-0.5}=0.39347

• If the bulb is in good condition at the end of 18 months, what is the probability that the bulb will be in good condition at the end of 24 months?

Let A and B be the events,

A = “The bulb will last at least 24 months”

B = “The bulb will last at least 18 months”

We want to find P(A | B).

By definition P(A | B) = P(A∩B)P(B)

but B⊂A, so  A∩B = B and  

\bf P(A | B) = P(B)P(B) = (P(B))^2

We have  

\bf P(B)=P(X>18)=1-P(X\leq 18)=1-(1-e^{-18/24})=e^{-3/4}=0.47237

hence,

\bf P(A | B)=(P(B))^2=(0.47237)^2=0.22313

• If the signal has six red bulbs, what is the probability that at least one of them needs replacement at the first inspection? Assume distribution of lifetime of each bulb is independent

If the distribution of lifetime of each bulb is independent, then we have here a binomial distribution of six trials with probability of “success” (one bulb needs replacement at the first inspection) p = 0.39347

Now the probability that exactly k bulbs need replacement is

\bf \binom{6}{k}(0.39347)^k(1-0.39347)^{6-k}

<em>Probability that at least one of them needs replacement at the first inspection = 1- probability that none of them needs replacement at the first inspection. </em>

This means that,

<em>Probability that at least one of them needs replacement at the first inspection =  </em>

\bf 1-\binom{6}{0}(0.39347)^0(1-0.39347)^{6}=1-(0.60653)^6=0.95021

5 0
3 years ago
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