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fredd [130]
1 year ago
7

FIND THE INDICATED PROBABILITY FOR THE FOLLOWING:

Mathematics
1 answer:
True [87]1 year ago
5 0

The value of the probability P(A and B) is 0.20

<h3>How to determine the probability?</h3>

The given parameters about the probability are

P(A or B) = 0.9

P(A) = 0.5

P(B) = 0.6

To calculate the probability P(A and B), we use the following formula

P(A and B) = P(A) + P(B) - P(A or B)

Substitute the known values in the above equation

P(A and B) = 0.5 + 0.6 - 0.9

Evaluate the expression

P(A and B) = 0.2

Hence, the value of the probability P(A and B) is 0.20

Read more about probability at

brainly.com/question/25870256

#SPJ1

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Answer:

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3 years ago
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Answer:

D

Step-by-step explanation:

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Answer:

Yes, it is a function

Step-by-step explanation:

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5 0
1 year ago
See attached image. For part b, my answer is <img src="https://tex.z-dn.net/?f=h%28t%29%3D%5Cfrac%7Bt%5E2%7D%7B100%7D-%5Cfrac%7B
ArbitrLikvidat [17]

Answer:

a) shown

b) h = [sqrt(17) - (5/2)t]²

c) t = 2sqrt(17)/5 seconds

Step-by-step explanation:

V = pi × r² × h

V = pi × 5² × h

V = 25pi × h

a) dV/dt = dV/dh × dh/dt

-5pi × sqrt(h) = 25pi × dh/dt

dh/dt = -sqrt(h)/5

b) 1/sqrt(h) .dh = -5. dt

2sqrt(h) = -5t + c

t = 0, h = 17

2sqrt(17) = 0 + c

c = 2sqrt(17)

2sqrt(h) = -5t + 2sqrt(17)

sqrt(h) = [2sqrt(17) - 5t] ÷ 2

sqrt(h) = sqrt(17) - (5/2)t

Square both sides

h = [sqrt(17) - (5/2)t]²

c) empty: h = 0

0 = [sqrt(17) - (5/2)t]²

sqrt(17) - (5/2)t = 0

(5/2)t = sqrt(17)

t = 2sqrt(17)/5

t = 1.64924225 seconds

sqrt: square root

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4 years ago
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Mumz [18]
(4 - -2) / (9 - 5) = 6/4 or 3/2
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