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SOVA2 [1]
3 years ago
14

If 4 tickets to a show cost $9, find the cost of 14 tickets.

Mathematics
2 answers:
hodyreva [135]3 years ago
7 0

Answer:

$31.50

Step-by-step explanation:

You would divide 9/4 which gets you 2.25, then you multiply 14x2.25 to get 31.5

Sveta_85 [38]3 years ago
4 0

Answer:

31.50

Step-by-step explanation:

We can write a ratio to solve

4 tickets             14 tickets

----------------- = ------------------

9 dollars             x dollars

Using cross products

4x = 9*14

4x =126

Divide each side by 4

4x/4 = 126/4

x =31.50

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The length of the radius of a bicycle wheel is 13 inches. Which of the following is closest to the
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234 inches

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8 0
3 years ago
A concert sold general admission tickets for $47.50 and lower-level seating for $97.50. The 995 tickets sold took in $68,762.50.
BabaBlast [244]

Answer: 565 general admission and 430 lower-level seating tickets sold (Answer (D))

Steps:

Let x be the number of general admission tickets, and y be the number of lower level tickets.

Set up the two equations:

68762.5 = x * 47.50 + y * 97.50       (total price as a sum of individual volumes)

x + y = 995    (sum of individual count = total count of tickets sold)

solve for x, y:

x = 995 - y

plug into the first equation:

68762.5 = (995-y) * 47.50 + y * 97.50

solve for y:

y = 430

then x = 565

x = 565 and y = 430


8 0
4 years ago
Read 2 more answers
Hola que es <br> 34+34+34+34+3+43+4+34+3+4+3
natka813 [3]

Answer: 230. 34 times five is 170. Then you are left with 170 + 3 + 43 + 4 + 3 +4 + 3. You can combine the 3's and you get 9. You are left with 179 + 4 +4 + 43 You combine the 4's and you get 187. 187 + 43 = 230.

4 0
3 years ago
Read 2 more answers
A part selected for testing is equally likely to have been produced on any one of six cutting tools.
JulijaS [17]

Answer:

a)S= (1,2,3,4,5,6)

b) 1/6 or 16.67%

c) 1/3 or 33.33%

d) 5/6 or 83.33%

Step-by-step explanation:

a) Sample space is the list of all the possible sample in this its either tool 1,2,3,4,5 or 6

b) probability of selecting from tool 1 is equally likely to picking from any cutting tool therefore it

1/6 or 16.7%

c) probability of selecting from any tool is 16.7% so probability of selecting from 3 or 5 = 16.67% + 16.67% = 33.3%

d) if the part is not from tool 4 then its from tool 1, or tool 2 or tool 3 or tool 5 or tool 6 therefore its

1/6+1/6+1/6+1/6+1/6 = 5/6 or 8.33%

8 0
3 years ago
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