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2 years ago

Express each fraction as a decimal:- 2 4/100

1 answer:

7 0

-0.24

this is because whenever it’s /100, the decimal at the back moves 2 twice

meaning it starts from -24. to -2.4 and lastly -0.24

whenever the dot ends at .24, a zero must be added

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A rectangular picture frame measures 27 cm by 48 cm. What is the perimeter or distance around the picture frame in meters

Firlakuza [10]

150, you just add the numbers

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3 years ago

If the number is divisible by both 2 and 3 then we can say the number is divided by

Sophie [7]

That number is divisible by 6.

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3 years ago

Why is the percent increase of 45 to 75 not equal to the percentage crease of 75 to 45 check all that apply.

nevsk [136]

Answer: B and F

Step-by-step explanation:

Since, In the first case original amount = 45

So, the increasing percentage when the original amount increases to 75,

= $\frac{75-45}{45} \times 100 = \frac{30}{45} \times 100= \frac{200}{3}$ %

In second case original amount = 75

So the decreasing percentage when the original amount decreases to 45,

= $\frac{75-45}{75} \times 100 = \frac{30}{75} \times 100= \frac{40}{1}$ %

Thus, We found that the ratio of the percent increase is not the same as the percent decrease ( because, $\frac{200}{3}\neq \frac{40}{1}$

Also, The original amount of the present increase is different from the original amount for the persons decrease. ( Because, $75\neq 45$

Therefore, Option B and F is correct only.

5 0

3 years ago

Read 2 more answers

Find the area of the part of the plane 3x 2y z = 6 that lies in the first octant.

gavmur [86]

The area of the part of the plane 3x 2y z = 6 that lies in the first octant is mathematically given as

A=3 √(4) units ^2

<h3>What is the area of the part of the plane 3x 2y z = 6 that lies in the first octant.?</h3>

Generally, the equation for is mathematically given as

The Figure is the x-y plane triangle formed by the shading. The formula for the surface area of a z=f(x, y) surface is as follows:

$A=\iint_{R_{x y}} \sqrt{f_{x}^{2}+f_{y}^{2}+1} d x d y(1)$

The partial derivatives of a function are f x and f y.

$\begin{aligned}&Z=f(x)=6-3 x-2 y \\&=\frac{\partial f(x)}{\partial x}=-3 \\&=\frac{\partial f(y)}{\partial y}=-2\end{aligned}$

When these numbers are plugged into equation (1) and the integrals are given bounds, we get:

$&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{(-3)^{2}+(-2)^2+1dxdy} \\\\&=\int_{0}^{2} \int_{0}^{3-\frac{3}{2} x} \sqrt{14} d x d y \\\\&=\sqrt{14} \int_{0}^{2}[y]_{0}^{3-\frac{3}{2} x} d x d y \\\\&=\sqrt{14} \int_{0}^{2}\left[3-\frac{3}{2} x\right] d x \\\\$

$&=\sqrt{14}\left[3 x-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3-\frac{3}{2} \cdot \frac{1}{2} \cdot x^{2}\right]_{0}^{2} \\\\&=\sqrt{14}\left[3.2-\frac{3}{2} \cdot \frac{1}{2} \cdot 3^{2}\right] \\\\&=3 \sqrt{14} \text { units }{ }^{2}$

In conclusion, the area is

A=3 √4 units ^2